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sdas [7]
3 years ago
9

In an 8.00km race, one runner runs at a steady 11.8 km/hr and another runs at 15.0 km/hr. How far from the finish line is the sl

ower runner when the faster runner finishes the race?
Physics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

The slower runner is 1.71 km from the finish line when the fastest runner finishes the race.

Explanation:

Given;

the speed of the slower runner, u₁ = 11.8 km/hr

the speed of the fastest runner, u₂ = 15 km/hr

distance, d = 8 km

The time when the fastest runner finishes the race is given by;

Time = \frac{Distance }{speed}\\\\Time = \frac{8}{15} \\\\Time = 0.533 \ hr

The distance covered by the slower runner at this time is given by;

d₁ = u₁ x 0.533 hr

d₁ = 11.8 km/hr x 0.533 hr

d₁ = 6.29 km

Additional distance (x) the slower runner need to finish is given by;

6.29 km + x = 8km

x = 8 k m - 6.29 km

x = 1.71 km

Therefore, the slower runner is 1.71 km from the finish line when the fastest runner finishes the race.

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andriy [413]

Answer:

85413.20177 W

2050.831684248 kWh

184.5748512 dollars

Explanation:

d = Diameter of blade = 100 m

r = Radius = \dfrac{d}{2}=\dfrac{100}{2}=50\ m

\eta = Efficiency = 0.34

\rho = Density of air = 1.25 kg/m³

V = Velocity of wind = 8 m/s

A = Area = \pi r^2

The power of a wind turbine is given by

P=\dfrac{1}{2}\rho AV^3\eta\\\Rightarrow P=\dfrac{1}{2}\times 1.25\times \pi\times 50^2\times 8^3\times 0.34\\\Rightarrow P=854513.20177\ W

The power is 85413.20177 W

Energy is given by

E=Pt\\\Rightarrow E=854513.20177\times 24\\\Rightarrow E=20508316.84248\ Wh\\\Rightarrow E=2050.831684248\ kWh

The energy is 2050.831684248 kWh

The revenue is given by

0.09\times 2050.831684248=184.5748512\$

The revenue generated is 184.5748512 dollars

6 0
3 years ago
For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin
makvit [3.9K]

Answer: 4.675×10^-6 m

Explanation: this is a question under the pattern gotten from an interference experiment.

The formulae below defines the experiment given

y = Rmλ/d

Where y = distance between the center fringe and any other fringe in the pattern = 8cm = 0.08m

m = position of fringe = 1 ( this is because we have only one central band)

λ = wavelength of light used for experiment = 680nm = 6.8×10^-7m

d = width of slit =?

R = distance between slits and screen = 5.5 cm = 0.055m

By substituting the parameters, we have that

0.08 = 0.055 × 1 × 6.8×10^-7/d

By cross multiplying, we have that

0.08 × d = 0.055 × 1 × 6.8×10^-7

d = 0.055 × 1 × 6.8×10^-7/ 0.08

d = 3.74 × 10^-7/ 0.08

d = 46.75×10^-7

d = 4.675×10^-6 m

5 0
3 years ago
An electrolytic cell can be used to plate gold onto other metal surfaces. The plating reaction is: Au (aq) e- --> Au(s) Notic
Dmitriy789 [7]

Answer:

Explanation:

Faraday’s constant can be used to convert the charge (Q) into moles of electrons (n). The charge is the current (I) multiplied by the time

Q = I × t = n × F

Where

Q is charge

I is current = 0.2A

t is time = ?

n is number of mole

F is Faraday constant = 96500C/s

Mass of Au = 0.4 g = 0.0004kg

Molar mass of Au = 197 g/mol

Malar mass = mass / mole

n = 0.4 / 197

n = 2.03× 10^-3 mol

n = 0.00203 mol

t = n × F / I

t = 0.00203 × 96500 / 0.2

t = 979.7 seconds

t = 16.32 minutes.

4 0
3 years ago
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kondaur [170]
The technical name was kinda given in the question, and I'm guessing that's what they want: Dispersion.  It refers to the phenomenon of different frequencies traveling at different speeds through a medium.  This is due to the fact that the relative electric permittivity is a complex quantity that is a function of frequency.  The relative electric permittivity, \epsilon_{r}, is related to the speed of the wave in the medium by the relation:
c' =  \frac{c}{ \sqrt{   \epsilon_{r}  } }
Since this speed is a function of permittivity, and permittivity is a function of frequency, speed is a function of frequency.
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3 years ago
While escaping from a building in which a fire is burning, 40 people pass through a smoky
kherson [118]

my bad  i clicked the wrong question to do sorry i wish i could help but im dumb lol

8 0
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