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3 years ago

A Universe Question!

Physics

1 answer:

vfiekz [6]3 years ago

4 0

I'm pretty sure this is A

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In its elemental state, carbon is available as:

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Twin skaters approach each other with identical speeds. Then, the skaters lock hands and spin. Calculate their final angular vel

kherson [118]

Answer:

$\omega=3.135rad/s$

Explanation:

From the question we are told that:

initial Speed $V_1=2.50$

Mass $m=70.0kg$

Center of mass $d=0.0.800m\$

Generally the equation for angular velocity is is mathematically given by

$\omega=\frac{v}{r}\\\\\omega=\frac{2.50}{0.0800}$

$\omega=3.135rad/s$

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Which of the following is not a primary cause of eroding rock

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Which characteristic would you expect from a sample with a pH of 9

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3 years ago

How many lenses with different focal lengths can be obtained by combining two surfaces whose radii of curvature are 4.00 cm and

Dovator [93]

Answer:

The lenses with different focal length are four.

Explanation:

Given that,

Radius of curvature R₁= 4

Radius of curvature R₂ = 8

We know ,

Refractive index of glass = 1.6

When, R₁= 4, R₂ = 8

We need to calculate the focal length of the lens

Using formula of focal length

$\dfrac{1}{f}=(n-1)(\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}})$

Put the value into the formula

$\dfrac{1}{f}=(1.6-1)(\dfrac{1}{4}+\dfrac{1}{8})$

$\dfrac{1}{f}=\dfrac{9}{40}$

$f=4.44\ cm$

When , R₁= -4, R₂ = 8

Put the value into the formula

$\dfrac{1}{f}=(1.6-1)(\dfrac{1}{-4}+\dfrac{1}{8})$

$\dfrac{1}{f}=-\dfrac{3}{40}$

$f=-13.33\ cm$

When , R₁= 4, R₂ = -8

Put the value into the formula

$\dfrac{1}{f}=(1.6-1)(\dfrac{1}{4}-\dfrac{1}{8})$

$\dfrac{1}{f}=\dfrac{3}{40}$

$f=13.33\ cm$

When , R₁= -4, R₂ = -8

Put the value into the formula

$\dfrac{1}{f}=(1.6-1)(\dfrac{1}{-4}-\dfrac{1}{8})$

$\dfrac{1}{f}=-\dfrac{9}{40}$

$f=-4.44\ cm$

Hence, The lenses with different focal length are four.

8 0

3 years ago