The
correct answer is A. In the combined gas law, if the volume is decreased and
the pressure is constant, then the temperature decreases.
<span>P1V1/
T1 = P2V2 / T2</span>
<span>Assume
the volume decrease by half; V2 = V1/2</span>
<span>P1V1/
T1 = P2V1 /2 T2</span>
<span>Cancelling
terms,</span>
<span>1/T1
= 1/2 T2</span>
T2
= T1/2
<span>Thus,
the temperature decreased.</span>
Answer: 3.79*10^24 atoms
Explanation:
1 mole = 6.02214076*10^23 atoms
I think the answer is ‘repulsion’
- From the general law of gases: PV = nRT,
where P is the pressure (atm),
V is the volume (L),
n is the number of moles,
R is the general gas constant (8.314 L.atm/mol.K),
T is the temperature in Kelvin
- at constant volume of the gas: P1T2 = P2T1
P1 = 3.20 atm, T1 = 300 K, T2 = 290 K, P2 = ??
(3.20 atm)(290 K) = P2(300 K)
P2 = (3.20 atm)(290 K)/ (300 K) = 3.093 atm
