Balanced equations illustrate what law?

5. Durante un estudio de la velocidad de la reacción A2(g) + 3B2(g)  2 AB3(g), se observa que en un recipiente cerrado que cont

weqwewe [10]

Answer:

a) Speed of the reaction = 0.002083 mol/L.s

b) The rate of disappearance of A₂ during this period of time = 0.002083 mol/L.s

c) The rate of appearance of AB₃ = 0.004167 mol/L.s

Explanation:

English Translation

During a study of the reaction rate

A₂ (g) + 3B₂ (g) → 2 AB₃ (g),

it is observed that in a closed container containing a certain amount of A₂ and 0.75 mol / L of B₂, the concentration B₂ decreases to 0.5 mol / L in 40 seconds.

a) What is the speed of the reaction?

b) What is the rate of disappearance of A₂ during this period of time?

c) What is the rate of appearance of AB₃?

Solution

The rate of a chemical reaction is defined as the time rate at which a reactant is used up or the rate at which a product is formed.

It is the rate of change of the concentration of a reactant (rate of decrease of the concentration of the reactant) or a product (rate of increase in the concentration of the product) with time.

Mathematically, for a balanced reaction

aA → bB

Rate = -(1/a)(ΔA/Δt) = (1/b)(ΔB/Δt)

The minus sign attached to the change of the reactant's concentration indicates that the reactant's concentration decreases.

And the coefficients of each reactant and product in the balanced reaction normalize the rate of reaction for each of them

So, for our given reaction,

A₂ (g) + 3B₂ (g) → 2 AB₃ (g)

Rate = -(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt) = (1/2)(ΔAB₃/Δt)

a) Speed of the reaction = Rate of the reaction

But we are given information on the change of concentration of B₂

Change in concentration of B₂ = ΔB₂ = 0.50 - 0.75 = -0.25 mol/L

Change in time = Δt = 40 - 0 = 40 s

(ΔB₂/Δt) = (-0.25/40) = -0.00625 mol/L.s

Rate of the reaction = -(1/3)(ΔB₂/Δt) = (-1/3) × (-0.00625) = 0.002083 mol/L.s

b) The rate of disappearance of A₂ during this period of time

Recall

Rate = -(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt)

-(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt)

Rate of disappearance of A₂ = -(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt) = (-1/3) × (-0.00625) = 0.002083 mol/L.s

c) The rate of appearance of AB₃

Recall

Rate = -(1/3)(ΔB₂/Δt) = (1/2)(ΔAB₃/Δt)

(1/2)(ΔAB₃/Δt) = -(1/3)(ΔB₂/Δt)

(ΔAB₃/Δt) = -(2/3)(ΔB₂/Δt)

rate of appearance of AB₃ = (ΔAB₃/Δt) = -(2/3)(ΔB₂/Δt) = (-2/3) × (-0.00625) = 0.004167 mol/L.s

Hope this Helps!!!

3 0

3 years ago

4. Describe the movement of the water molecules at cold temperatures.

kenny6666 [7]

Answer:

Point out to students that molecules of hot water are moving faster and are slightly further apart. The molecules of cold water are moving slower and are a little closer together. If students do not notice a difference, move the slider all the way to the left again and then quickly to the right.

2. How do molecules move in cold water?

Compare the speed of molecules in hot water compared to molecules in cold water? Water molecules move faster in hot water and slower in cold water. water molecules in cold, room temperature, and hot water. most of the liquid.

3 0

3 years ago

Which major changes in human society and the environment occurred during the Industrial Revolution? *

wariber [46]

Answer: c

Explanation:

during the industrial revolution americans were switching from rural to urban life, thus using up more fossil fuels, and working in factories

7 0

3 years ago

For each trial, compute the mol of titrant; (molarity x L) and keep the number of significant figures to 4.

MrMuchimi

Answer:

Trial Number of moles

1 0.001249mol

2 0.001232mol

3 0.001187 mol

Explanation:

To calculate the number of moles of tritant you need its molarity.

Since the molarity is not reported, I will use 0.1000M (four significant figures), which is used in other similar problems.

Molarity is the concentration of the solution in number of moles of solute per liter of solution.

In this case the solute is NaOH.

The formula is:

$Molarity=\dfrac{\text{Number of moles of solute}}{\text{Volume of solution in liters}}$

Solve for the number of moles:

$\text{Number of moles}=Molarity\times Volume\text{ }in\text{ }liters$

Then, using the molarity of 0.1000M and the volumes for each trial you can calculate the number of moles of tritant.

Trial mL liters Number of moles

1 12.49 0.01249 0.01249liters × 0.1000M = 0.001249mol

2 12.32 0.01232 0.01232liters × 0.1000M = 0.001232mol

3 11.87 0.01187 0.01187liters × 0.1000M = 0.001187 mol

3 0

3 years ago

Read 2 more answers

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?

kotegsom [21]

Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

5 0

3 years ago