Answer: 363 Ω.
Explanation:
In a series AC circuit excited by a sinusoidal voltage source, the magnitude of the impedance is found to be as follows:
Z = √((R^2 )+〖(XL-XC)〗^2) (1)
In order to find the values for the inductive and capacitive reactances, as they depend on the frequency, we need first to find the voltage source frequency.
We are told that it has been set to 5.6 times the resonance frequency.
At resonance, the inductive and capacitive reactances are equal each other in magnitude, so from this relationship, we can find out the resonance frequency fo as follows:
fo = 1/2π√LC = 286 Hz
So, we find f to be as follows:
f = 1,600 Hz
Replacing in the value of XL and Xc in (1), we can find the magnitude of the impedance Z at this frequency, as follows:
Z = 363 Ω
Answer:
a) , b) , ,
Explanation:
a) The system mass-spring is well described by the following equation of equilibrium:
After some handling in physical and mathematical definition, the following non-homogeneous second-order linear differential equation:
The solution of this equation is:
The velocity function is:
Initial conditions are:
Equations at are:
The spring constant is:
After some algebraic handling, amplitude and phase angle are found:
The position can be described by this function:
b) The period of the motion is:
The amplitude is:
The phase of the motion is:
Answer:
i really thought that said hater
Answer: I think the answer is d
Explanation: sry if wrong