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Oliga [24]
3 years ago
12

If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.

8
Physics
1 answer:
Schach [20]3 years ago
6 0

Answer:

The magnitude of each charge is 2.82\times10^{-6}\ C

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

F=\dfrac{kq^2}{r^2}

Where, q = charge

r = separation

Put the value into the formula

20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}

q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}

q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}

q=2.82\times10^{-6}\ C

Hence, The magnitude of each charge is 2.82\times10^{-6}\ C

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Anna35 [415]
(a) Period of the wave
The period of a wave is the time needed for a complete cycle of the wave to pass through a certain point.
So, if an entire cycle of the wave passes through the given location in 5.0 seconds, this means that the period is equal to 5.0 s: T=5.0 s.

(b) Frequency of the wave
The frequency of a wave is defined as
f= \frac{1}{T}
since in our problem the period is T=5.0 s, the frequency is
f= \frac{1}{5.0 s}=0.2 Hz

(c) Speed of the wave
The speed of a wave is given by the following relationship between frequency f and wavelength \lambda:
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8 0
3 years ago
Vector vector a has a magnitude of 29 units and points in the positive y-direction. when vector vector b is added to vector a ,
Nutka1998 [239]
Good morning.

We have:

\mathsf{\overset{\to}{a} = 29\overset{\to}{j}}

Where j is the unitary vector in the direction of the y-axis.

We have that 

\mathsf{\overset{\to}{a}+\overset{\to}{b} = -18\overset{\to}{j}}

We add the vector -a to both sides:

\mathsf{\overset{\to}{b} = -18\overset{\to}{j} -\overset{\to}{a} = -18\overset{\to}{j} -29\overset{\to}{j}}\\ \\ \mathsf{\overset{\to}{b}=-47\overset{\to}{j}}


Therefore, the magnitude of b is 47 units.
5 0
2 years ago
Read 2 more answers
A police car chases a speeder along a straight road towards a cliff both vehicles move at 160km/h the siren on the police car pr
natta225 [31]

Answer:

f ’= 97.0 Hz

Explanation:

This is an exercise of the doppler effect use the frequency change due to the relative movement of the fort and the observer

in this case the source is the police cases that go to vs = 160 km / h

and the observer is vo = 120 km / h

the relationship of the doppler effect is

          f ’= f₀ (v + v₀ / v- v_{s})

let's reduce the magnitude to the SI system

            v_{s} = 160 km / h (1000 m / 1km) (1h / 3600s) = 44.44 m / s

            v₀ = 120 km / h (1000m / 1km) (1h / 3600s) = 33.33 m / s

we substitute in the equation of the Doppler effect

          f ‘= 100 (330+ 33.33 / 330-44.44)

          f ’= 97.0 Hz

4 0
3 years ago
Roughly to what height would a 5 kg stone need to be raised in order to have the same stored energy as the energy stored in the
hoa [83]

8.16m is the required height, a 5kg stone need to be raised.

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We obtain the formula by considering the work done in raising a mass m through a height h.

Work in elevating mass m through height h is equal to force times distance.

The force must be greater than the mass m's weight, hence F = mg.

Work done = mgh = gravitational potential energy

Energy =  Mass of the object × gravitational acceleration × height.

Mass of the stone = 5kg

Equating ;

∴ 400 J = 5 kg × 9.8 m/s² × height

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Therefore, 8.16m is the required height.

Learn more about energy here:

brainly.com/question/1242059

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8 0
2 years ago
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dmitriy555 [2]

Answer:

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Explanation:

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