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zepelin [54]
3 years ago
7

AN AIR CRAFT HEADS NORTH AT 320KM/H RELATIVE TO THE WIND THE WIND VELOCITY IS 80KM/HFROMNORTH .FIND THE VELOCITY OF THE AIR RELA

TIVE TO THE GROUND
Physics
1 answer:
makkiz [27]3 years ago
5 0

Answer:

Explanation:

See attached file for answer.

Download docx
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Zoning laws establish _______.
Aleonysh [2.5K]

Answer:

Zoning ordinances detail whether specific geographic zones are acceptable for residential or commercial purposes. Zoning ordinances may also regulate: - size

- placement

- density

- height of structures

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

5 0
3 years ago
Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan
elena55 [62]

Answer:

10.07m/s^2

Explanation:

Information we have:

velocities:

initial velocity: v_{i}=0mph (starts from rest)

final velocity: v_{f}=50mph

time:  t=2.22s

Since we need the answer in m/s^2, we nees to convert the speed to meters per second:

v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s

We find the acceleration with the following formula:

a=\frac{v_{f}-v_{i}}{t}

substituting the known values:

a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2

the acceleration is 10.07m/s^2

8 0
3 years ago
Read 2 more answers
Which property of light is not explained by the wave model of light?
Ronch [10]

Blue light can knock electrons off a plate, but red light can't

5 0
3 years ago
Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3​
kobusy [5.1K]

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

8 0
3 years ago
A mine elevator is supported by a single steel cable 0.0125 m in diameter. The total mass of the elevator cage and occupants is
Sonja [21]

Answer:

0.8895m

Explanation:

Cable diameter = 0.0125m

Mass of elevator = 6450kg

Young Modulus(E) = 2.11*10¹¹N/m

∇l (change in length) =

L = 362m

A = Πr², but r = d / 2 = 0.0125 / 2 = 0.00625m

A = 3.142 * (0.00625)² = 1.227*10^-4m²

Young Modulus (E) = Tensile stress / Tensile strain

E = (F / A) / ∇l / L

F = mg = 6450 * 9.8 = 63210N

2.11*10¹¹ = (63210 / 1.22*10^-4) / (∇l / 362)

2.11*10¹¹ = 5.18*10⁸ / (∇l / 362)

2.11*10¹¹ = (5.18*10⁸ * 362) / ∇l

2.11*10¹¹ = 1.875*10¹¹ / ∇l

∇l = 1.875*10¹¹ / 2.11*10¹¹

∇l = 0.8895m

The change in length is 0.8895m

8 0
3 years ago
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