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2 years ago

Physics Physics Physics - 10

Physics

1 answer:

Svetach [21]2 years ago

7 0

Answer:

1.Pulley

2. Wheel and axle

3. Screw

4. wedge

5. Incline

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Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10

11111nata11111 [884]

Answer:

$1.62\times 10^{-8}\ \text{s}$

Explanation:

$\epsilon_0$ = Vacuum permittivity = $8.854\times 10^{-12}\ \text{F/m}$

$A$ = Area = $10\times 2\times 10^{-4}\ \text{m}^2$

$d$ = Distance between plates = 1 mm

$V_c$ = Changed voltage = 60 V

$V$ = Initial voltage = 100 V

$R$ = Resistance = $1000\ \Omega$

Capacitance is given by

$C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.854\times 10^{-12}\times 10\times 2\times 10^{-4}}{1\times 10^{-3}}\\\Rightarrow C=1.7708\times 10^{-11}\ \text{F}$

We have the relation

$V_c=V(1-e^{-\dfrac{t}{CR}})\\\Rightarrow e^{-\dfrac{t}{CR}}=1-\dfrac{V_c}{V}\\\Rightarrow -\dfrac{t}{CR}=\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-CR\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-1.7708\times 10^{-11}\times 1000\ln(1-\dfrac{60}{100})\\\Rightarrow t=1.62\times 10^{-8}\ \text{s}$

The time taken for the potential difference to reach the required level is $1.62\times 10^{-8}\ \text{s}$ .

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3 years ago

A mover applies a net force of 28 N to a sofa that has a mass of 70 kg.

Alinara [238K]

Answer: .4 m/s^2= acceleration

Explanation:

f = m*a

We can rearrange this equation to solve for acceleration. Therefore,

a=f/m

a= 28N/70kg

a= 0.4 m/s^2

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3 years ago

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3 years ago

A lever has an effort arm that is 8 meters long and the resistance arm that is 1.5 meters long, how much effort is needed to lif

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We are given with two measurements of the arm and an input weight. To answer this problem,we need to balance the forces and use the lengths of the arms.
209 N * 8 m = x * 1.5 m
x = 1114.67 N

it takes 1114.67 N to lift the input weight

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3 years ago

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A white car is traveling at the legal speed limit v0 along an interstate highway. A blue car traveling in the same direction at

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Answer:

the distance between two cars becomes $d = \frac{v_o^2}{2a_b}$ when blue car travels at legal speed