Which type of spectrum does the illustration A

2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??

Zepler [3.9K]

Answer:

$d=1.78\times 10^{-7}\ Dg/\mu m^3$

Explanation:

Given,

The density of Helium is $1.78\times 10^4\ g/cm^3$

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

$d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3$

So, the density of Helium is equal to $1.78\times 10^{-7}\ Dg/\mu m^3$ .

4 0

3 years ago

Any change in average weather conditions on Earth that lasts for at least several decades is called

sladkih [1.3K]

Answer:climate change

Explanation:

8 0

3 years ago

When did Darwin publicly share his views of evolution?

Veronika [31]

Answer:

It was not until he was 50 years old, in 1859.

Explanation:

4 0

4 years ago

Select all steps below that you followed to practice laboratory safety during the experiment. used tongs or a test tube holder t

uysha [10]

Explanation:

Steps followed to practice laboratory safety during the experiment are as follows.

Used tongs or a test tube holder to hold materials over the Bunsen burner flame.
Wore gloves and goggles.
Made careful observations of the products and reactants.
Did not smell the gases produced.

When we heat a test tube over bunsen flame then the tube gets hot and when we hold it with bare hands then out hands will burn. Therefore, it is advised to hold test tube with the help of tongs or a holder so that our hands did not burn.

We should also wear gloves and goggles so that any acid would not spill directly on our hands, skin and eyes as it can affect or damage the skin severely.

Careful observations were made so that correct calculations about the experiment can be carried out.

It is also advised that we should not smell the gases produced but gases move freely from one place to another in a laboratory or any where else.

So, we can try to avoid it by covering our mouth with a cloth but we cannot stop it. If we keep on inhaling the gases produced in a laboratory then it can also lead to severe disease or defect in the human body.

8 0

3 years ago

Read 2 more answers

If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w

irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

C + O₂ -------------> CO₂

1 mol 1 mol 1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

C + O₂ -------------> CO 1 mol (12 g/mol) 1 mol (32 g/mol) 1 mol (44 g/mol)

C + O₂ -------------> CO₂

12 g 32 g 44 g

So,

we come to know that 32 g of Oxygen combine with 12 g of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

32 g of O₂ ≅ 12 g of C

11 g of O₂ ≅ g of C

by doing cross multiplication

g of C = 12 g x 11 g / 32 g

g of C = 132 g / 32 g

g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

12 g of C ≅ 44 g of CO₂

4.13 g of C ≅ g of CO₂

by doing cross multiplication

g of CO₂ = 44 g x 4.13 g / 12 g

g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0

3 years ago