A tuning fork starts to vibrate when a certain note is played on the piano. this is an example of?

Which of these objects must have the greatest force acting on it? pls help fast

8_murik_8 [283]

Let's look at Newton's second law

F=ma

Force is directly proportional towards mass

If mass is more force will be more.

Between baseball and bowling ball Bowling ball has higher mass

So it would expert most force

Option D

8 0

2 years ago

It's a good idea to create your procedure so that it's written _____. A. on a computer B. after your conclusions C. with step-by

Dahasolnce [82]

The answer is C. step by step

8 0

3 years ago

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A 15.0 cm diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the

velikii [3]

Answer:0.0144 tesla

Explanation:

Magnetic field strength is the same as Magnetomotive force

B= I/2πr

B=magnetic field strength

I=current

r=radius=0.15/2=0.75m

Area=πr2= 1.77m2

torqueT= NIABsin theta

B= T/NIABsin theta

B=0.135/1 * 5.3 * 1.77 *sin90

B=0.0144 tesla

6 0

3 years ago

An acrobat performs with a swing, as shown in the diagram . Which of these most likely happens as the acrobat moves from Point 1

UkoKoshka [18]

Acrobat part
A
Plants
b
Rocks
C

6 0

4 years ago

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A car leaves an intersection traveling west. Its position 4 sec later is 21 ft from the intersection. At the same time, another

Alex_Xolod [135]

Answer:

15.8 ft/s

Explanation:

$\frac{da}{dt}$ = Velocity of car A = 9 ft/s

a = Distance car A travels = 21 ft

$\frac{db}{dt}$ = Velocity of car B = 13 ft/s

b = Distance car B travels = ft

c = Distance between A and B after 4 seconds = √(a²+b²) = √(21²+28²) = √1225 ft

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

$2a\frac{da}{dt}+2b\frac{db}{dt}=2c\frac{dc}{dt}\\\Rightarrow a\frac{da}{dt}+b\frac{db}{dt}=c\frac{dc}{dt}\\\Rightarrow \frac{dc}{dt}=\frac{a\frac{da}{dt}+b\frac{db}{dt}}{c}\\\Rightarrow \frac{dc}{dt}=\frac{21\times 9+28\times 13}{\sqrt{1225}}\\\Rightarrow \frac{dc}{dt}=15.8\ ft/s$

∴ Rate at which distance between the cars is increasing three hours later is 15.8 ft/s

6 0

4 years ago