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3 years ago

How to know what gases have more effusion?

Chemistry

1 answer:

OlgaM077 [116]3 years ago

6 0

Answer:

If you have ever been in a room when a piping hot pizza was delivered, you have been made aware of the fact that gaseous molecules can quickly spread throughout a room, as evidenced by the pleasant aroma that soon reaches your nose. Although gaseous molecules travel at tremendous speeds (hundreds of meters per second), they collide with other gaseous molecules and travel in many different directions before reaching the desired target.

Explanation:

hope this helps

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What is the mass percent of oxygen (0) in SO2?

vazorg [7]

Answer:

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

5 0

3 years ago

The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b

weeeeeb [17]

Answer:

The answer is " $\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}$ "

Explanation:

When $HCI$ is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

$CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\$

In this, the $CH_3COOH$ is a weak acid so, it not completely dissociated.

$CH_3COONa \ (aq) \ \ and \ NaCl$ were strong electrolytes they are completely dissociated.

The $HCl$ is a strong acid so, it is completely dissociated So, the net ionic equation is:

$CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)$

8 0

3 years ago

When CO2(g) is put in a sealed container at 730 K and a pressure of 10.0 atm and is heated to 1420 K , the pressure rises to 24.

d1i1m1o1n [39]

Answer:

48%

Explanation:

Based on Gay-Lussac's law, the pressure is directly proportional to the temperature. To solve this question we must assume the temperature increases and all CO2 remains without reaction. The equation is:

P1T2 = P2T1

<em>Where Pis pressure and T absolute temperature of 1, initial state and 2, final state of the gas:</em>

P1 = 10.0atm

T2 = 1420K

P2 = ?

T1 = 730K

P2 = 10.0atm*1420K / 730K

P2 = 19.45 atm

The CO2 reacts as follows:

2CO2 → 2CO+ O2

Where 2 moles of gas react producing 3 moles of gas

Assuming the 100% of CO2 react, the pressure will be:

19.45atm * (3mol / 2mol) = 29.175atm

As the pressure rises just to 24.1atm the moles that react are:

24.1atm * (2mol / 19.45atm) = 2.48 moles of gas are present

The increase in moles is of 0.48 moles, a 100% express an increase of 1mol. The mole percent that descomposes is:

0.48mol / 1mol * 100 = 48%

8 0

3 years ago

A great white shark has resided at a depth where the pressure is 16 atm. If the initial volume of its swim bladder is 4 L, what

padilas [110]

Answer:

The new volume of the gas is 32L

Explanation:

P1 = 16atm

V1 = 4L

P2 = atm

V2 = ?

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (16 * 4) / 2

V2 = 64 / 2

V2 = 32L

The new volume of the gas is 32L

6 0

3 years ago

I can be found in the 4th period on the periodic table.

Rainbow [258]

Vanadium (V)

Vanadium is the only one in the 4th period here so

4 0

3 years ago