From he calculations, we can see that the total pressure at equilibrium is 21 atm.
<h3>What is equilibrium constant?</h3>
The term equilibrium constant commonly describes the constant that that shows the extent of conversion of reactants to products.
We have to find the pressure of each gas as follows;
For H2
P = nRT/V = 4.553 /2 × 0.082 × 1000/8.89 L = 21 atm
Using the ICE table;
C(s) + 2H2(g) ⇌ CH4(g)
I 21 atm 0
C -x +x
E 21 - x x
0.263= x/(21 - x )^2
0.263(21 - x )^2 = x
38 - 11x - 0.263x^2 = x
0.263x^2 + 12x - 38 = 0
x=2.97 atm
At equilibrium, we have;
(21 - 2.97) + 2.97 = 21 atm
Learn more about equilibrium constant: brainly.com/question/17960050
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
Mass of S produced = 0.36 mol x 32 g/mol = 11.5 g of S is produced
I'm pretty sure it's organic chemistry.
