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3 years ago

This is heat transfer due to differences in density

Physics

2 answers:

Gala2k [10]3 years ago

8 0

Answer:

convection

Explanation:

Heat transfer by convection is caused by differences of temperature and density within a fluid.

Gekata [30.6K]3 years ago

8 0

Answer:

This flow transfers heat from one part of the fluid to another. Heat transfer by convection is caused by differences of temperature and density within a fluid. Density is a measure of how much mass there is in a volume of a substance.

Explanation: hope this helped ;3

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What are the output waveforms of the following waves, after passing through a transformer?

Ber [7]

The output waveforms after passing through the transformer actually depend on the type of transformer used. It could either be a step-up transformer (steps voltage up), or a step-down transformer (steps voltage down). Both transformers have an output voltage in a form of a sine wave.

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3 years ago

Given the two sets, which statement is true?<br><br> A = {1, 2}<br> B = {1, 2, 3, 4}

Mnenie [13.5K]

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3 years ago

Which statements describe both male and female reproductive systems? Check all that apply. A:The reproductive system produces ho

Scilla [17]

Answer: A:The reproductive system produces hormones.

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C:The reproductive system produces reproductive cells.

Explanation:

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4 0

3 years ago

Read 2 more answers

In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 609 nm.

Ray Of Light [21]

Answer:

$\Delta x = 3.65 \mu m$

Explanation:

As we know that the sixth order maximum will have path difference given as

$\Delta x = N\lambda$

here we know that

N = order of maximum

$\lambda = 609 nm$

now we have

$N = 6$

so we know that

$\Delta x = 6(609 nm)$

$\Delta x = 3.65 \mu m$

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3 years ago

A house is losing heat at a rate of 1600 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Exp

Setler [38]

Answer:

1600 kJ/h per K, 888.88 kJ/h per °F and 888.88kJ/h per R

Explanation:

We make use of relations between temperature scales with respect to degrees celsius:

$1 K= 1^{\circ}C+273\\1^{\circ}F= (1^{\circ}C*1.8)+32\\1 R= (1^{\circ}C*1.8)+491.67$

This means that a change in one degree celsius is equivalent to a change of one kelvin, while for a degree farenheit and rankine this is equivalent to a change of 1.8 on both scales.

So:

$\frac{Q}{\Delta T(K)}=\frac{Q}{\Delta T(^\circ C)}=1600 \frac{kJ}{h} per K\\\frac{Q}{\Delta T(^\circ F)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per ^\circ F\\\frac{Q}{\Delta T(R)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per R$

5 0

3 years ago