Monosaccharides and disaccharides are types of

A certain gasol occupies a volume of 12.5 L at 50 degree Celsius and 740 torr. what would its volume be at STP? do the equation

Charra [1.4K]

n=PV/RT

convert:

740 torr to atm (1 atm=760 torr)

50 degree celsius to kelvin ( degree celsus +273= kelvin)

n=(0.9737 atm)(12.5L)÷(0.08206 L atm mol ⁻¹k⁻¹) (323 K)

n=0.4592 mols×22.4 L/1 mol. (22.4 L STP= 1 mol)

=10.286 L at STP

it could be this

4 0

2 years ago

It is relatively easy to change the temperature of a substance that:_______

Taya2010 [7]

Answer:

b. has a low specific heat capacity.

Explanation:

Hello,

In this case, since the specific heat is defined as the heat required to increase or decrease 1 degree Celsius 1 gram or mole of a specific substance, we infer that the lower the specific heat, the less energy will be needed for such increase or decrease, therefore, it turns out easier to modify the temperature in a substance that b. has a low specific heat capacity.

Best regards.

4 0

3 years ago

Determine the number of protons, neutrons, and electrons in the following:

Finger [1]

The ⁴⁰₁₈X is the symbol for ⁴⁰₁₈Ar - atom and it has 18 protons, 18 electrons, and 22 neutrons.

<h3>What is Mass number ?</h3>

Mass number is the sum of the numbers of protons and neutrons present in the nucleus of an atom.

In the given element, ⁴⁰₁₈X, Subscript 18 is the number of proton and is also equal to the number of electron. While supercript 40 is the atomic mass.

The number of neutrons is given by subtracting the proton number from the mass number.

Therefore,

Number of Neutron = Mass Number - Atomic Number

= 40 - 18

= 22 Neutrons

Learn more about Mass number here ;

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8 0

1 year ago

1. What are different ways that genetic technology is used?

Reil [10]

Answer:

In medicine, genetic engineering has been used to mass-produce insulin, human growth hormones, follistim, human albumin, monoclonal antibodies, antihemophilic factors, vaccines, and many other drugs. In research, organisms are genetically engineered to discover the functions of certain genes.

Explanation:

4 0

2 years ago

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Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005 g sample of menthol is comb

Bogdan [553]

Answer: The molecular formula for the menthol is $C_{10}H_{20}O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.2829g$

Mass of $H_2O=0.1159g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.2829 g of carbon dioxide, $\frac{12}{44}\times 0.2829=0.077g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 0.1159 g of water, $\frac{2}{18}\times 0.1159=0.0129g$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.1005) - (0.077 + 0.0129) = 0.0106 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.077g}{12g/mole}=0.0064moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0129g}{1g/mole}=0.0129moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.0106g}{16g/mole}=0.00066moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00066 moles.

For Carbon = $\frac{0.0064}{0.00066}=9.69\approx 10$

For Hydrogen = $\frac{0.0129}{0.00064}=19.54\approx 20$

For Oxygen = $\frac{0.00066}{0.00066}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 10 : 20 : 1

Hence, the empirical formula for the given compound is $C_{10}H_{20}O_1=C_{10}H_{20}O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 156.27 g/mol

Mass of empirical formula = 156 g/mol

Putting values in above equation, we get:

$n=\frac{156.27g/mol}{156g/mol}=1$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 10)}H_{(1\times 20)}O_{(1\times 1)}=C_{10}H_{20}O$

Thus, the molecular formula for the menthol is $C_{10}H_{20}O$

4 0

2 years ago

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