1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ira [324]
3 years ago
7

The given graduated cylinder is calibrated in

Chemistry
2 answers:
Reptile [31]3 years ago
8 0

For this case, the first thing you should do is observe the level of the liquid in the graduated cylinder, where it is located.

This will result in its volume.

We have then that the volume is given by:

V = 26mL

Answer:

the volume of liquid in the graduated cylinder is:

V = 26mL

777dan777 [17]3 years ago
8 0

Answer : The volume of liquid in graduated cylinder is, 20.6 mL.

Explanation :

As we know that for the measurement of the volume of liquid in graduated cylinder are shown by placing the graduated cylinder on the flat surface and then view the height of the liquid in the graduated cylinder with the naked eyes directly level with the liquid.

The liquid will tend to curve downward that means this curve is known as the meniscus.

In the case of colored liquid, we are always read the upper meniscus of the liquid for the measurement.

In the case of colorless liquid, we are always read the lower meniscus of the liquid for the measurement.

In the given image, there are 10 division between the 20 and 30 and the smallest division is, 0.1 and the solution is colored. So, the volume of liquid will be, 20 ml + 0.6 ml = 20.6 ml.

Hence, the volume of liquid in graduated cylinder is, 20.6 mL.

You might be interested in
Can a pillow have kinetic and potential energy explain how and why ?
romanna [79]

Answer:

no

Explanation:

because its fabric

6 0
3 years ago
Read 2 more answers
When all colors are absorbed, you see:<br><br> black<br> white<br> green<br> yellow
wolverine [178]

uhmm, white.

Explanation:

you'll basically look like blind ig

5 0
3 years ago
How many moles are in 18.2 g of CO2?<br> 41.4 moles<br> 801 moles<br> 0.414 moles<br> 0 2.42 moles
mrs_skeptik [129]

Answer:

0.414 mole (3 sig. figs.)

Explanation:

Given grams, moles = mass/formula weight

moles in 18.2g CO₂(g) = 18.2g/44g/mole = 0.413636364 mole (calc. ans.)

≅ 0.414 mole (3 sig. figs.)

6 0
3 years ago
Help me, please. I Don't get my homework.
Lisa [10]
We’d have to be very careful because if we had our skeletons on the outside it’d be very easy to injure ourselves
7 0
4 years ago
Read 2 more answers
Sprinkler powder on the carron board _________ friction​
VARVARA [1.3K]

Answer:

Sprinkling of powder on the carom board <u>reduces</u> friction.

5 0
3 years ago
Read 2 more answers
Other questions:
  • Example 1: urea, (nh2)2co, is used in the manufacture of resins and glues. when 5.00 g of urea is dissolved in 250.0 ml of water
    7·2 answers
  • Which of the following is true of atoms with very high electronegativity?
    5·1 answer
  • How many moles of oxygen can be formed from 250 grams of aluminum oxide
    6·1 answer
  • Matter is anything that has mass. What is the smallest unit of matter known as?
    6·1 answer
  • If the volume of water in a cylinder is 8.0mL, but changes to 10.0mL when a solid is carefully lowered into it, the volume of th
    15·1 answer
  • What is the molarity of a solution in which 25.3 grams of potassium bromide is dissolved in 150. mL of solution?
    8·2 answers
  • Temperature, according to the kinetic molecular theory, is a measure of intermolecular attraction.
    7·1 answer
  • What two elements are present in the compounds in the last two rows of table 4​
    6·1 answer
  • A large hamburger sandwich contains 628 kcal and 36 grams of fat. Approximately what percentage of the total energy is contribut
    9·1 answer
  • Swift has a balloon of gas at 64psi. The volume of the balloon is 6.958L. If the volume of the balloon is reduced to 3L. what wi
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!