Answer:
Los 0.0416km
esto se debe a que transponemos la fórmula acelerada y obtenemos Distancia = velocidad × tiempo
también recuerda transponer los segundos a horas viendo que la velocidad es por hora
También tenga en cuenta que no hablo español, así que esto fue extremadamente difícil
culto
The answer is b
300,000 km
Answer:
a) 
b) 
c) 
Explanation:
From the question we are told that
Distance to Betelgeuse 
Mass of Rocket 
Total Time in years traveled 
Total energy used by the United States in the year 2000 
Generally the equation of speed of rocket v mathematically given by


where




Therefore


b)
Generally the equation of the energy E required to attain prior speed mathematically given by


c)Generally the equation of the energy
required to accelerate the rocket mathematically given by



Temperature is the energy