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IrinaVladis [17]
3 years ago
11

which of the following is not an example of force? A. magnetism B. Electric force C. energy D. friction​

Physics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

Friction​

Explanation:

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Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface _____________ is less than
alisha [4.7K]

Answer:

Traction

Explanation:

Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface Traction is less than ideal.

Traction is an act of drawing or pulling something over a surface specially a road or a track or it also defined as the grip of a tire on road or a wheel on rail. So speed when entering a curve should be slower when the tire has low traction to avoid accident.

5 0
3 years ago
What is speed of wave in terms of frequency and wavelength??​
ratelena [41]

Answer:

In the case of a wave, the speed is the distance traveled by a given point on the wave (such as a crest) in a given interval of time. In equation form, If the crest of an ocean wave moves a distance of 20 meters in 10 seconds, then the speed of the ocean wave is 2.0 m/s.

Speed = Wavelength x Wave Frequency. In this equation, wavelength is measured in meters and frequency is measured in hertz (Hz), or number of waves per second. Therefore, wave speed is given in meters per second, which is the SI unit for speed.

Explanation:

can i get the crown please

3 0
2 years ago
Two blocks of masses m and M are connected by a string and pass over a frictionless pulley. Mass m hangs vertically, and mass M
horsena [70]

Answer:

sin\theta - \mu_k cos\theta = \frac{m}{M}

sin\theta - \mu_k cos\theta = 1

Explanation:

Force of friction on M mass so that it will move down the inclined plane is given as

F_f = \mu Mgcos\theta

now if it is moving down the inclined plane at constant speed

so we will have

Mgsin\theta - T - \mu mgcos\theta = 0

on other side the mass "m" will go up at constant speed

so we have

T - mg = 0

so we have

Mgsin\theta = \mu Mgcos\theta + mg

so we have

sin\theta - \mu_k cos\theta = \frac{m}{M}

for special case when m = M

then we have

sin\theta - \mu_k cos\theta = 1

5 0
3 years ago
When work is done and a force is transferred which choice describes the movements of the object?
Arisa [49]
When work is done and a force is transferred an object must move
3 0
4 years ago
Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb
Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

w = 2*pi*f

where f is the frequency, and:

T = 1/f.

Then we can write:

w = 2*pi/T

and our equation becomes:

ar = r*(2*pi/T)^2

Now we solve this for r.

First we need to use the same units in both equations, so we want to write T in seconds.

T = 88 days,

A day has 24 hours, and one hour has 3600 seconds:

T = 88*24*3600 s =7,603,200s

Then:

3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2

r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters

5 0
3 years ago
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