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Umnica [9.8K]
3 years ago
5

A water skier is pulled behind a boat. When the skis push down on the water, what is the reaction force?

Physics
2 answers:
IrinaVladis [17]3 years ago
8 0
The answer is C) The water pushed up on the skis

The water reacts to the downward force of the skis by pushing back up against the skis. 
statuscvo [17]3 years ago
8 0

Answer:

the water pushes up on the skis

Explanation:

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4 years ago
Please help fast!!
daser333 [38]

The answer is C..........      

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3 years ago
Write relationship between hertz and megahertz​
dusya [7]

Explanation:

1 mega Hertz = 1000000 hertz

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3 years ago
If its wavelength were doubled, its energy would be If its wavelength were doubled, its energy would be 4E. 2E. 12E. 14E.
ANEK [815]

The wavelength was doubled, and its energy will be increased by 4 times.

looking at the formula

energy E = MC^2

also, c = \lambda \times \nu

hence it is clear from above that energy is directly proportional to the square of the wavelength.

hence, The wavelength was doubled, and its energy will be increased by 4 times.

<h3>What is Wavelength?</h3>
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  • The spatial frequency is the reciprocal of the wavelength. The Greek letter lambda is frequently used to represent wavelength.
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To learn more about wavelength with the given link

brainly.com/question/13533093

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5 0
2 years ago
A train pulls away from a station with a constant acceleration of 0.42 m/s2. A passenger arrives at a point next to the track 6.
Rina8888 [55]

Answer:

2.69 m/s

Explanation:

Hi!

First lets find the position of the train as a function of time as seen by the passenger when he arrives to the train station. For this state, the train is at a position x0 given by:

x0 = (1/2)(0.42m/s^2)*(6.4s)^2 = 8.6016 m

So, the position as a function of time is:

xT(t)=(1/2)(0.42m/s^2)t^2 + x0 = (1/2)(0.42m/s^2)t^2 + 8.6016 m

Now, if the passanger is moving at a constant velocity of V, his position as a fucntion of time is given by:

xP(t)=V*t

In order for the passenger to catch the train

xP(t)=xT(t)

(1/2)(0.42m/s^2)t^2 + 8.6016 m = V*t

To solve this equation for t we make use of the quadratic formula, which has real solutions whenever its determinat is grater than zero:

0≤ b^2-4*a*c = V^2 - 4 * ((1/2)(0.42m/s^2)) * 8.6016 m =V^2 - 7.22534(m/s)^2

This equation give us the minimum velocity the passenger must have in order to catch the train:

V^2 - 7.22534(m/s)^2 = 0

V^2 = 7.22534(m/s)^2

V = 2.6879 m/s

4 0
3 years ago
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