Answer:
The limiting reactant is H₂
Explanation:
The reaction of hydrogen (H₂) and carbon monoxide (CO) to produce methanol (CH₃OH) is the following:
2H₂(g) + CO(g) → CH₃OH(g)
From the balanced chemical equation, we can see that 1 mol of CO reacts wIth 2 moles of H₂. So, the stoichiometric ratio is:
2 mol H₂/1 mol CO = 2.0
We have 500 mol of CO and 750 mol of H₂, so we calculate the ratio to establish a comparison:
750 mol H₂/500 mol CO = 1.5
Since 2.0 > 1.5, we have fewer moles of H₂ than are needed to completely react with 500 moles of CO. In fact, we need 1000 moles of H₂ and we have 750 moles. So, the limiting reactant is H₂.
The answer is C. 146g because you add all of the masses of the individual elements and then mulyiply by 1.72 to get your answer.
"CH3CH2CH2CH2OH " is known by the name of "n-butanol" and "CH3CH(OH)CH3" is known by the name of "<span>Isopropyl alcohol". These two given products are basically alcohols. I hope that this is the answer that you were looking for and the answer has actually come to your desired help. Thanks for joining brainly and getting your questions solved.</span>
