VOLUMEEEE IS THE CORRECT ANSWER
there should be less liquid at the end of the experiment since heating liquid is an endothermic process, and endothermic processes typically break the bonds between liquids. The applied heat would soon break the bonds that hold the molecules of the liquid together, and evaporation would occur once the temperature is hot enough. Thus, the evaporated water would decrease the volume of the liquid.
This is a question about the colligative property known as freezing point depression. Freezing point depression (the amount the normal freezing point of the solvent is decreased) can be calculated with this equation:
ΔT = i Kf<span> m
</span>
Where i (the van't Hoff factor) is the degree of dissociation of the solute, Kf is the freezing point depression constant, and m is the molality of the solution.
Here i = 2 (KCl dissociates into 2 ions, K+ and Cl-), Kf = 1.86 C/m (for water), and m = 0.743m).
ΔT = 2 x 1.86 C/m x 0.743m = <span>2.764C
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That means the freezing point of the solution is 2.764C less than the pure solvent (water), making it 0C - 2.764C = -2.764C.
