A student investigates a pure metal, X. The student takes a 100.0 g piece of metal X, heats it

How are atoms of the same element with different mass numbers called?

ELEN [110]

Answer:

Isotopes

Explanation:

Isotopes are the same element with different masses because of the different number of neutrons. Also, the element doesn't change. If we change the protons, the element will change and then it won't be an isotope. Hope it helps!

7 0

2 years ago

What is the balanced equation for: Ammonium Carbonate and Magnesium Sulfate react to yield Ammonium Sulfate plus Magnesium Carbo

Debora [2.8K]

Answer:

(NH₄)₂CO₃ (aq) + MgSO₄(aq) → (NH₄)₂SO₄(aq) + MgCO₃ (s) ↓

Explanation:

We determine the reactants:

(NH₄)₂CO₃ → Ammonium carbonate

MgSO₄ → Magnesium sulfate

We determine the products:

(NH₄)₂SO₄ ; MgCO₃

All the salts from carbonates are precipitates:

(NH₄)₂CO₃ (aq) + MgSO₄(aq) → (NH₄)₂SO₄(aq) + MgCO₃ (s) ↓

Ratio is all 1:1. 1 mol of ammonium carbonate reacts to 1 mol of magnessium sulfate in order to produce 1 mol of ammonium sulfate and 1 mol of magnessium carbonate.

5 0

3 years ago

A sailboat is pushed by a steady wind with a force of 4000 N. Its acceleration is 2

AveGali [126]

Answer:

Explanation:

The mass of the sailboat can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{4000}{2} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

Please help ill medal and fan!

krok68 [10]

Solutions for your questions are the following:
1. remaining amount is equal to:960 g : 100% = 30 g : xx = 30 g * 100% / 960 g
= 3.125%
= 0.03125
Now, we use this formula to calculate the number of half-lives:(1/2)ⁿ = x,
so,(1/2)ⁿ = 0.03125
to calculate n, use this equation:
n*log(1/2) = log(0.03125) n = log(0.03125)/log(1/2)
= log(0.03125)/log(0.5)
= -1.505/-0.301
n=5

Ifn = 5T = 15 min

Then
L = T/nL = 15 min/5
= 3 minutes

2. You should pick filtration. It is use to separate heterogeneous mixtures just like in the problem stated.

6 0

3 years ago

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0

3 years ago