Answer:
5.7
Explanation:
(C₂H₅)₃NHCl dissociates according to the following equation.
(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻
The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.
(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.
Ka × Kb = Kw
Ka = Kw / Kb
Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴
Ka = 1.9 × 10⁻¹¹
(C₂H₅)₃NH⁺ dissociates according to the following equation.
(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺
We can calculate [H⁺] using the following expression.
[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶
The pH is:
pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7
Answer:
Physical
Explanation: Because it says "Until creamy" meaning you're changing the look, not the way it reacts with each other.
Answer:
The correct answer is 4.16 grams.
Explanation:
Based on the given information, the concentration of KCl solution is 16 % m/v, which means that 100 ml of the solution will contain 16 grams of KCl.
The molarity of the solution can be determined by using the formula,
M = weight/molecular mass × 1000/Volume
The molecular mass of KCl is 74.6 grams per mole.
M = 16/74.6 × 1000/100
M = 16/74.6
M = 2.14 M
Now the weight of KCl present in the solution of 26 ml will be,
2.14 = Wt./74.6 × 1000 /26
Wt. = 4.16 grams
Molarity is defined as the moles of solute per liter of solution. 
. Where M is molarity, n is the number of moles and V is the volume. First we must find the molar mass of 
which is 109.98 g/mol
Then we find the molarity using above equation
Answer:
6s
Explanation:
Barium is in group 2 of the s block and is in period 6.
