Answer:
10.6 moles of CO₂ are produced in this combustion
Explanation:
The combustion reaction is:
2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (g)
We assume the ethane as the limiting reactant because the excersise states that the O₂ is in excess.
We make a rule of three:
2 moles of ethane can produce 4 moles of CO₂
Therefore 5.30 moles of ethane will produce (5.3 . 4) /2 = 10.6 moles
Answer:
Percentage recovery of acetylferrocene = 81.6%
Explanation:
Mass of the sample mixture = 22.092 g
Ratio of mixture of acetylferrocene and ferrocene = 1 : 1
This means that the sample conatains equal amounts of acetylferrocene and ferrocene.
Therefore the mass of each sample in the mixture = 22.092 g / 2 = 11.046 g
Mass of acetylferrocene recovered = 9.017 g
Percentage recovery of acetylferrocene = (mass of recovered/ mass in sample) * 100%
Percentage recovery of acetylferrocene = (9.017 g / 11.046 g) *100%
Percentage recovery of acetylferrocene = 81.6%
Answer:
the molecular formula of paradichlorobenzene is C6H4CL2
Answer:
Tree sap flows over the leaf and preserves it.
Explanation:
Amber would preserve the image.
