Xe +f2 →Xef2
ΔXe = ΣB.P reactants - Σ B.d products
-108k.s/ mol = B. D f₂ - 2 B.D xe-f
-108 k.s/mol =155 k.s/mol - 2B.Dxe-f
263kJ/mol/2 = B. D xe-f
B.D xef = 131.5 kJ/mol
132 kJ/mol
POH will be -log[conc of OH]
-log (3.9E-08) = 7.409
pH = 14- pOH
pH = 14 - 7.409
pH = 6.59
The aim is to use less space while demonstrating the distribution of electrons in shells
If you want to depict how an atom's electrons are scattered across its subshells, an orbital notation is more suited.
This is due to the fact that some atoms have unique electronic configurations that are not readily apparent from textual configurations.
<h3>How does electron configuration work?</h3>
The placement of electrons in orbitals surrounding an atomic nucleus is known as electronic configuration, also known as electronic structure or electron configuration.
<h3>What sort of electron arrangement would that look like?</h3>
- For instance: You can see that oxygen contains 8 electrons on the periodic table.
- These 8 electrons would fill in the following order: 1s, 2s, and finally 2p, according to the aforementioned fill order. O 1s22s22p4 would be oxygen's electron configuration.
learn more about electronic configuration here
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Answer:
86,400 seconds in a day.
Explanation:
There are 24 hrs in a day. So there are 2460 mins in a day. ( 1hr=60 mins) So there are 246060 seconds in a day. (1 min = 60 seconds) Therefore 86,400 seconds in a day.
