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kvasek [131]
3 years ago
5

Una pelota de béisbol sale despedida de un bate con una velocidad horizontal de 20 m/s. En un tiempo de 0.25 s, ¿a qué distancia

habrá viajado horizontalmente y cuánto habrá caído verticalmente?
Physics
1 answer:
Tpy6a [65]3 years ago
4 0

Answer:

Translation:

A baseball is thrown from a bat with a horizontal speed of 20 m / s. In a time of 0.25 s, how far will you have traveled horizontally and how much will you have fallen vertically?

Explanation:

This question deals directly with projectile motions and we can use modifications of equation of motion since it's a horizontal motion.

(a). How far will it have travelled;

X = Vo * t

X = 20 * 2.5 = 50m

(b). How much will it have fallen vertically?

y = Voy + ½gt²

But Voy = 0

y = ½ * 9.8 * 2.5²

y = 30.625m

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Natural gas is non renewable energy.

Explanation:

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Explain why an aton is neutral
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How is the radiating electric field (or electromagnetic signal) produced when radio stations broadcast
Natali5045456 [20]

Answer:

Radio stations have dipole type antennas

this field increases in intensity and propagates outwards,

Explanation:

Radio stations have dipole type antennas, that is, all sides are isolated from each other, when the AC signal from the radio station arrives, the lcharge begins at times and by the Lens law a field appears that opposes this movement, this field increases in intensity and propagates outwards, when the voltage reaches a maximum, the generated wave also reaches the maximum, now the incident wave begins to decrease, an electric hand appears to oppose this prisoner, and in this way a cap is created. electric .

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3 years ago
The battleship and enemy ships 1 and 2 lie along a straight line. Neglect air friction. battleship 1 2 Consider the motion of th
DaniilM [7]

Answer:

\frac{t_1}{t_2} = \frac{sin\theta_1}{sin\theta_2}

Explanation:

The vertical component of the initial velocities are

v_v = v_0sin\theta

If we ignore air resistance, and let g = -9.81 m/s2. The the time it takes for the projectiles to travel, vertically speaking, can be calculated in the following motion equation

v_vt - gt^2/2 = s = 0

t(v_v - gt/2) = 0

v_v - gt/2 = 0

t = 2v_v/g = 2v_0sin\theta/g

So the ratio of the times of the flights is

t_1 / t_2 = \frac{2v_0sin\theta_1/g}{2v_0sin\theta_2/g} = \frac{sin\theta_1}{sin\theta_2}

8 0
3 years ago
3. A dog walks a distance of 100 ft. in 20 s of time. What is the dog's
natta225 [31]
The answer is A.
100/20=5
8 0
3 years ago
Read 2 more answers
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