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snow_lady [41]
3 years ago
11

A 16.0 kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 25.0 N. Starting from rest, the

sled attains a speed of 1.00 m/s in 8.00 m. Find the coefficient of kinetic friction between the runners of the sled and the snow. You Answered
Physics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

\mu_k = 0.15

Explanation:

according to the kinematic equation

v^{2} - u^{2} = 2aS

Where

u is initial velocity  = 0 m/s

a = acceleration

S is distance = 8.00 m

final velocity = 1.0 m/s

a = \frac {v^{2}}{2S}

a = \frac {1{2}}{2*8.6}

a = 0.058 m/s^2

from newton second law

Net force = ma

f_{net} = ma

F - f = ma

25 - \mu_kN = ma

25 - \mu_kmg = ma

\frac {25 - ma}{mg} =\mu_k

\frac {25 - 16*0.058}{16*9.81} = 0.15

\mu_k = 0.15

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