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babunello [35]
3 years ago
6

How many moles of hci are needed to form 230 moles of ci2?

Chemistry
1 answer:
LekaFEV [45]3 years ago
4 0
<span>The answer is 335 dm³.</span>
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From his experiments ,j.j Thomson concludes what?
Vladimir [108]

Answer:

Thomson made the following conclusions: The cathode ray is composed of negatively-charged particles. The particles must exist as part of the atom, since the mass of each particle is only ∼ 20001​start fraction, 1, divided by, 2000, end fraction the mass of a hydrogen atom.

Explanation:

7 0
3 years ago
Read 2 more answers
Jada Peterson
barxatty [35]

Answer: A

Explanation:

4 0
3 years ago
If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
Ostrovityanka [42]

Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

Answer:

The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

(1.50-x)M            (2.5+x)

The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

2.5=\frac{2.5+x}{(1.50-x)}

x = 0.36 M

The equilibrium concentration of each gas:

[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M

[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M

3 0
3 years ago
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 3.30kg of water at 23.8°C. Dur
Brums [2.3K]

Answer:

T_2= 31.9\°C

Explanation:

Hello there!

In this case, it is possible to propose an energy balance in order to illustrate how the heat released by the reaction is absorbed by the water:

-Q_{rxn}=Q_{water}

Thus, since the heat released by the reaction is -112 kJ (-112000 J), it is possible to define the hear absorbed by the water in terms of mass, specific heat and temperature change:

-(-112000J)=m_{water}C_{water}(T_2-T_1)

In such a way, it is possible to define the final temperature as shown below:

T_2=23.8\°C+\frac{112000J}{3300g*4.18\frac{J}{g\°C} }\\\\T_2= 31.9\°C

Best regards!

4 0
3 years ago
How many atoms are there in 5.70 mol of hanfnium?
ANTONII [103]

The correct answer would be 3.49 times 10^ minus 24 molecules

6 0
3 years ago
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