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3 years ago

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Multiply and simplify.

1 answer:

miv72 [106K]3 years ago

8 0

Multiply and simplify (3 + i)(4 + 2i)

(3 + i)(4 + 2i) = (3*4) + (3*2i) + (4*i) + (2i*i) = 12 + 6i + 4i + 2i^2

i^2 = -1

12 + 6i + 4i + 2i^2 = 12 + 6i + 4i -2 = 10 + 10i

Use the imaginary number i to rewrite the expression:

- $-\sqrt{-16} \\(-1)\sqrt{(-1)16}\\(-1)\sqrt{16}i\\(-1)4i\\-4i$

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What is a benefit of health Insurance?

vaieri [72.5K]

Answer:

Health insurance protects you from unexpected, high medical costs. You pay less for covered in-network health care, even before you meet your deductible. You get free preventive care, like vaccines, screenings, and some check-ups, even before you meet your deductible.

Step-by-step explanation:

5 0

3 years ago

I have to get this so I pass help plz

pshichka [43]

Answer:

$\boxed{\sf x=-2}$

$\boxed{\sf y=-4}$

Step-by-step explanation:

<u>First, Let's solve for x in -2x+2y=-4:</u>

$\sf -2x+2y=-4$

<u>Subtract 2y from both sides:</u>

$\sf -2x+2y-2y=-4-2y$

$\sf -2x=-4-2y$

<u>Divide both sides by -2:</u>

$\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}$

$\bold{ x=y+2}$

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

$\sf 3x+3y=-18$

→ let x=2+y

$\sf 3\bold{(2+y)}+3y=-18$

<u>Simplify:</u>

$\sf 6+6y=-18$

<u>Now, let's solve for y in 6+6y=-18</u>

$\sf 6+6y=-18$

<u>Subtract 6 from both sides:</u>

$\sf 6+6y-6=-18-6$

$\sf 6y=-24$

<u>Divide both sides by 6:</u>

$\sf \cfrac{6y}{6}=\cfrac{-24}{6}$

$\bold{ y=-4}$

<u>Now, substitute y=-4 into x=2+y:</u>

$\sf x=2+y$

→ let y = -4

$\sf x=2+\bold{-4}$

$\bold{x=-2}$

Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

5 0

2 years ago

Evaluate 0.3 + y/2 when y = 10 and z =5

Vladimir79 [104]

Answer:

0.3*10+10/5

PEMDAS (left to right)

3+2

5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If the equation says that one cookie with 10 chips plus another cookie with 10 chips plus another cookie with 10 chips equal 30.

Shtirlitz [24]

Wait what I don’t understand

6 0

3 years ago

Read 2 more answers

Find the sum of the series given in sigma notation.

Kryger [21]

Answer:

Option b is correct 175

Step-by-step explanation:

n = 7

k = 6

3k -2 ------1

put k = 6 in above eq. for finding first term

a1 = 3(6) - 2 = 18 - 2 = 16

put k = 7 in above eq. for finding first term

a2 = 3(7) - 2 = 21 - 2 = 19

a3 = 3 (8) - 2 = 24 - 2 = 22

16, 19 , 22, ... //Arithmetic series formation

a1 = 16 , a2 = 19

d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms

Using sum forumula for arithmetic series

sum = $\frac{n}{2}(2a1 + (n-1)d)$

= $\frac{7}{2}(2a1 + (7-1)d)$

= $\frac{7}{2}(2(16) + (6)3)$

= $\frac{7}{2}(32 + 18)$

= $\frac{7}{2}(50)$

= 7 * 25

= 175

4 0

3 years ago