Answer:
t(s) is in rejection zone then we reject H₀.
Bad weather indeed make apples weight decrease
Step-by-step explanation:
Normal Distribution
population mean μ₀ = 9.5 ou
sample size = n = 16 then we should apply t-student table
degree of fredom df = n - 1 df = 16 - 1 df = 15
1.-Test hypothesis
H₀ null hypothesis μ₀ = 9.5
Hₐ alternative hypothesis μ₀ < 9.5
One left tail-test
2.-Confidence level 95 %
α = 0,05 and df = 15 from t-student table we get t(c) = - 1.761
3.-Compute t(s)
t(s) = [ μ - μ₀ ] /√s/n t(s) = (9.32 - 9.5 )* √16 / 0.18
t(s) = - 0.18*√16 / 0.18
t(s) = - 4
4.-Compare t(s) and t(c)
t(s) < t(c) -4 < - 1.761
Then t(s) is in the rejection zone.
5.- Decision
t(s) is in rejection zone then we reject H₀.
Farmer conclude that bad weather make apples weight decrease
Answer:
A i think its a A try. it it that looks correct
Answer:
You could say +3 and -2 or +4 and -1
Step-by-step explanation:For example if you draw a number line
count 1 hump between each line. it equals 5.
|_______|_______|_______|_______|_______|
-2 -1 0 1 2 3
Answer:
The required inequalities are 
and 
.
Step-by-step explanation:
Consider the provided information.
Daniel moves no more than 30 of his sheep and goats into another field.
Let s represent the number of sheep and g represent the number of goats.
No more than means the number of sheep and goats should be less than or equal to 30.
For less than or equal to use the inequality ≤
Hence the required inequality is:
More than 7 of his animals are sheep.
This can be represented as:
Hence, the required inequalities are and .
