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3 years ago

9

Soils can be quite differnt from one another due mainly to the differnt amounts of ____ they contain

1 answer:

Elan Coil [88]3 years ago

3 0

Sand,silt,clay and organic matter

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Normally, atoms are electrically neutral because there are__.

spayn [35]

Answer:

Equal number of protons and electrons

Explanation:

This principle of proton and electron equality was used by J.J. Thompson in the discovery of proton. After he had discovered the electron. He discovered that since atoms are electrically neutral, that means there must be equal number of protons to balance out the electrons present in the atom.

8 0

3 years ago

a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block

Airida [17]

Answer:

577g

Explanation:

Given parameters:

Temperature change = 5.9°C

Amount of heat lost = 427J

Unknown:

Mass of the block = ?

Solution:

The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

H = m c Ф

H is the heat capacity

m is the mass of the block

c is the specific heat capacity

Ф is the temperature change

Specific heat capacity of lead is 0.126J/g°C

m = H / m Ф

m = $\frac{427}{0.126 x 5.9}$ = 577g

Mass of the lead block is 577g

7 0

3 years ago

A street light is at the top of a 13.0 ft. tall pole. A man 6.3 ft tall walks away from the pole with a speed of 3.5 feet/sec al

amm1812

Answer:

$\dfrac{dL}{dt}=5.82 \ ft/s$

Explanation:

given,

street light height = 13 ft

man height = 6.3 ft

speed of the man = 3.5 ft/sec

$\dfrac{H}{L} = \dfrac{h}{l}$

$\dfrac{H}{L} = \dfrac{h}{L-x}$

$\dfrac{L}{H} = \dfrac{L-x}{h}$

hL = H(L-x)

hL = HL-Hx

$L = \dfrac{Hx}{H-h}$

$L = \dfrac{13x}{13-6.3}$

L = 1.94 x

$\dfrac{dL}{dt}=\dfrac{dL}{dx}\dfrac{dx}{dt}$

$\dfrac{dL}{dt}=1.94\times 3$

$\dfrac{dL}{dt}=5.82 \ ft/s$

7 0

3 years ago

A dog travels 18 meters south across the backyard in 11 seconds. What is the dog's speed?

o-na [289]

The dog’s speed is
A) 0.61 m/s

4 0

4 years ago

A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg

lidiya [134]

Answer:

7.5 kg

Explanation:

We are given that

$m_1=10 kg$

Length of plank, l=3 m

Distance of fulcrum from one end of the plank=1 m

$m_2=20 kg$

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

$20\times 1=10\times (1.5-1)+m\times (1.5+0.5)$

$20=10(0.5)+2m$

$20=5+2m$

$2m=20-5=15$

$\implies m=\frac{15}{2}$

$m=7.5 kg$

Hence, mass 7.5 kg must be on the other end if the plank remains balanced.

3 0

3 years ago

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