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3 years ago

Substitution y=× +5 2x-y=-2

2 answers:

3 0

We know what y equals already.

y = x + 5

2x - x + 5 = -2
x + 5 = -2
-5 -5

x = -7

y = -7 + 5
y = -2

Now we have our values

Answer: (-7,-2)
or
x = -7
y = -2

zubka84 [21]3 years ago

3 0

So, we substitute the y in the second equation to solve for x-value.

2x-(x+5) = -2
2x-x-5 = -2
x-5 = -2
+5 +5
x = 3

As we got the x-value, we now have to find the value of y.

y = x+5
y = 3+5
y = 8

So, the answer is (3,8)

HOPE THIS HELPS!!!!!

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Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8

Blababa [14]

$w(s,t)=f(u(s,t),v(s,t))$

From the given set of conditions, it's likely that you are asked to find the values of $\dfrac{\partial w}{\partial s}$ and $\dfrac{\partial w}{\partial t}$ at the point $(s,t)=(1,0)$ .

By the chain rule, the partial derivative with respect to $s$ is

$\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}$

and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21$

Similarly, the partial derivative with respect to $t$ would be found via

$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5$

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3 years ago

12^2<br><br> 28 questions left

Vesnalui [34]

Answer:

144

Step-by-step explanation:

12² is the same as 12 × 12

12 × 12 = 144

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2 years ago

Which pairs of polygons are congruent?

Alla [95]

Answer: Pair 1 and Pair 4

Step-by-step explanation:

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3 years ago

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550 tickets were sold for a game for a total of $712.50. If adult tickets sold for $1.50 and children's tickets sold for $1.00,

EastWind [94]

9514 1404 393

Answer:

adult: 325
children's: 225

Step-by-step explanation:

It usually works well to let a variable represent the higher-value item in the mix. Here, we can let 'a' represent the number of adult tickets sold. Then the total revenue is ...

1.50a +1.00(550 -a) = 712.50

0.50a = 162.50 . . . . . . . . . . . . . subtract 550 and collect terms

a = 325

c = 550 -325 = 225

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3 years ago

A chemist is mixing two solutions, solution A and solution B Solution A is 15% water and solution Bis 20% water. She already has

slavikrds [6]

Answer:

15 mL of the solution with 20% water will be needed.

Step-by-step explanation:

Use the inverse relationship

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x = 10 mL * (3/2) = 15 mL

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3 years ago

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