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3 years ago

Which interactions and processes contribute to the dissolution of ionic compounds in water?

Chemistry

1 answer:

Tanya [424]3 years ago

3 0

Explanation:

Polarity is defined as the development of partial charges on the atoms of a molecule. In a water molecule, there are hydrogen and oxygen atoms.

Due to the difference in electronegativity of both hydrogen and oxygen atom there is development of partial positive charge on hydrogen atom and a partial negative charge on oxygen atom.

So, when bond between hydrogen and oxygen will break down then it will form hydrogen ions ( $H^{+}$ ) and oxygen ions ( $O^{2-}$ ).

Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule.

When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.

So, oxygen atom has an affinity towards cations and hydrogen atom has an affinity for anions.

Thus, we can conclude that following interactions and processes contribute to the dissolution of ionic compounds in water:

1. Affinity of oxygen towards cations

2. Ion–dipole interactions

4. Hydration

6. Affinity of hydrogen towards anions

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Answer:

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Explanation:

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Mazyrski [523]

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<h3>What is equilibrium state?</h3>

Equilibrium of any reaction is that state in which concentration of reactant and concentration of product will be constant.

Given chemical reaction is:

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From the equilibrium state reaction will move only that side which will contribute to maintain the stable state. In the forward reaction heat is released as mention in the question. So, when the temperature of reaction is increased then it shifts towards the left side by absorbing the heat and maintain the stability.

Hence, option (2) is correct, i.e. It will shift to the left because heat is absorbed.

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Answer:

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Explanation;

sorry im late, hopefully this can help somebody :)

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Sophie [7]

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<h3>Sectional division</h3>

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