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scZoUnD [109]
3 years ago
5

Which interactions and processes contribute to the dissolution of ionic compounds in water?

Chemistry
1 answer:
Tanya [424]3 years ago
3 0

Explanation:

Polarity is defined as the development of partial charges on the atoms of a molecule. In a water molecule, there are hydrogen and oxygen atoms.

Due to the difference in electronegativity of both hydrogen and oxygen atom there is development of partial positive charge on hydrogen atom and a partial negative charge on oxygen atom.  

So, when bond between hydrogen and oxygen will break down then it will form hydrogen ions (H^{+}) and oxygen ions (O^{2-}).

Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule.

When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.

So, oxygen atom has an affinity towards cations and hydrogen atom has an affinity for anions.

Thus, we can conclude that following interactions and processes contribute to the dissolution of ionic compounds in water:

1. Affinity of oxygen towards cations

2. Ion–dipole interactions

4. Hydration

6. Affinity of hydrogen towards anions

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A combustion analysis of 5.214 g of a compound yields 5.34 g co 2 ​ , 1.09 g h 2 ​ o, and 1.70 g n 2 ​ . if the molar mass of th
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Answer is: C₃H₃N₃O₃.
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m(CₐHₓNₓ) = 5,214 g.
m(CO₂) = 5,34 g.
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n(CO₂) = n(C) =  5,34 g ÷ 44 g/mol = 0,121 mol.
n(H₂O) = 1,09 g ÷18 g/mol = 0,06 mol.
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n(N₂) = 1,7 g ÷ 28 g/mol = 0,0607 mol.
n(N) = 0,0607 mol · 2 = 0,121 mol.
n(C) : n(H) : n(N) = 0,121 mol : 0,121 mol : 0,121 mol /: 0,121
n(C) : n(H) : n(N) = 1 : 1 : 1.
M(CHN) = 27 g/mol.
m(O₂) = 8,13 g - 5,214 g = 2,914 g.
n(O₂) = 2,914 g ÷ 32 g/mol = 0,09 mol.
n(CₓHₓNₓOₓ) = 5,214 g ÷ 129,1 g/mol = 0,0404 mol.
n(CₓHₓNₓOₓ) : n(CO₂) = 1 : 3.


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