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3 years ago

How do make friends and other people like being around u also im lonely

Physics

2 answers:

nadya68 [22]3 years ago

6 0

A good way to do that is to talk abt anything, TALK MORE NOT LESS:)

Roman55 [17]3 years ago

5 0

Answer:

I'm a lonely person too. It would be good if you found someone that are respectful.If someone approaches you, accept them.

Explanation:

But its not that easy to make friends especially when your shy and a introvert. Slowly make a progress to socialize.

You can try to impress them with your talent or kindness and humor.

As long as they are a good person. Always help people and they would automatically help you back and I believe a friendship will be bonded.

Hope this helped :D

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In the bedroom of your house you would like to run a 240 W toward, a 30 W alarm clock, a 720 W tanning bed, and four 60 W lights

erica [24]

Answer: current = 10.25A

Explanation:

Toward = 240w

Alarm clock = 30w

Tanning bed = 720w

4 60 watts bulb = 60 * 4 = 240w

Total power = 240 + 30 + 720 + 240 = 1230w

Voltage = 120v

Recall that Power = current * voltage

1230 = current * 120

current = 1230/120 = 10.25A

3 0

3 years ago

to keep everything the same between the man and the boy, the table below for the mans motion covers the same interval as the one

mixer [17]

Answer:

I hope this helps

Explanation:

i had to submit just to get the answer,Have a great day!!!

5 0

3 years ago

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o

inysia [295]

Answer:

vertical distance, s = 0.16 meters

Explanation:

It is given that,

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.

Dashboard is placed at a distance of 2.7 meters.

Calculating time from velocity and distance i.e. $t=\dfrac{d}{s}=\dfrac{2.7}{15}\ s=0.18\ s$

Using second equation of motion for finding vertical distance :

$s=ut+0.5gt^2$

Here, u = 0 (for vertical velocity )

$s=0.5gt^2$

$s=0.5\times 10\times (0.18)^2$

s = 0.162 meters

or s = 0.16 meters

Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.

3 0

3 years ago

Jane plans to fly from Binghamton, New York, to Springfield, Massachusetts, about 280 km due east of Binghamton. She heads due e

aleksklad [387]

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

5 0

3 years ago

A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago