Answer:
<u>We are given:</u>
initial velocity (u) = 20m/s
acceleration (a) = 4 m/s²
time (t) = 8 seconds
displacement (s) = s m
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<u>Solving for Displacement:</u>
From the seconds equation of motion:
s = ut + 1/2 * at²
replacing the variables
s = 20(8) + 1/2 * (4)*(8)*(8)
s = 160 + 128
s = 288 m
Answer:
Mass of Jupiter = 4.173×10^15kg
Explanation:
Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:
T^2 = GM/4 pi × r^3
Where G = universal gravitational constant
r = radius
M = masd of jupiter
Rearranging the formular to make M the subject of formular
T^2 × 4 pi = G M × r^3
(T^2 × 4 pi) / (G× r^3) = M
(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3
M = 19.32 /6.672×10^-11)(4.11×10^8)^3
M = 19.32 / 4.63 ×10^15
M = 4.173×10^15kg
Answer:
Fractional error = 0.17
Percent error = 17%
F = 112 ± 19 N
Explanation:
Plug in the values to find the force:
F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N
Find the fractional error:
ΔF/F = Δm/m + 2Δv/v + Δr/r
ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5
ΔF/F = 0.17
Multiply by 100% to find the percent error:
ΔF/F × 100% = 17%
Solve for the absolute error:
ΔF = 0.17 × 112 N = 19 N
Therefore, the force is:
F = 112 ± 19 N
Answer:
This is your answer
Explanation:
Actually I took this from go ogle
