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3 years ago

If two twins (54 kg each) were 0.02 m apart, what is the force of gravity between them?

Physics

1 answer:

Lelechka [254]3 years ago

3 0

Answer:

Force, $F=4.86\times 10^{-4}\ N$

Explanation:

We have,

Masses of two twins are 54 kg each

They are placed at a distance of 0.02 m

It is required to find the force of gravity between them. The formula used to find the gravitational force between masses is given by :

$F=G\dfrac{m_1m_2}{r^2}$

plugging all the known values:

$F=6.67\times 10^{-11}\times \dfrac{54^2}{(0.02)^2}\\\\F=4.86\times 10^{-4}\ N$

So, the force of gravity between them is $4.86\times 10^{-4}\ N$ .

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What is the relationship between momentum and kinetic energy.

Margaret [11]

Answer:

constant object, momentum increases directly with speed

Explanation:

whereas kinetic energy increases the square of the velocity due to energy momentum

6 0

2 years ago

A horizontal object-spring system oscillates with an amplitude of 2.8 cm. If the spring constant is 275 N/m and object has a mas

Lisa [10]

Answer:

(a) the mechanical energy of the system, U = 0.1078 J

(b) the maximum speed of the object, Vmax = 0.657 m/s

Explanation:

Given;

Amplitude of the spring, A = 2.8 cm = 0.028 m

Spring constant, K = 275 N/m

Mass of object, m = 0.5 kg

(a) the mechanical energy of the system

This is the potential energy of the system, U = ¹/₂KA²

U = ¹/₂ (275)(0.028)²

U = 0.1078 J

(b) the maximum speed of the object

$V_{max} =\omega*A= \sqrt{\frac{K}{M} } *A\\\\V_{max} = \sqrt{\frac{275}{0.5} } *0.028\\\\V_{max} = 0.657 \ m/s$

$a_{max} = \frac{KA}{M} \\\\a_{max} = \frac{275*0.028}{0.5}\\\\a_{max} = 15.4 \ m/s^2$

6 0

3 years ago

Calculate the heat required, in calories, to raise

Goshia [24]

Answer: $Q=4450.74\ J$

Explanation:

Given

mass of tin $m=100 gm$

Also we know that

specific heat of tin $c_{tin}=0.21 J/gm-^{\circ}C$

Melting Point of Tin $T=231.94^{\circ}C$

Heat required to raise the temperature of 100 gm tin is given by

$Q=mc\Delta T$

where $Q=heat\ added$

$c=specific\ heat\ of\ tin$

$\Delta T=change\ in\ temperature$

$Q=100\times 0.21\times (231.94-20)$

$Q=4450.74\ J$

5 0

3 years ago

A person pushes two boxes with a horizontal force F of magnitude of 100 N.

Monica [59]

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

$m_A = 9\ kg$

Mass of box B,

$m_B = 2 \ kg$

Horizontal force,

$F_{app} = 100 \ N$

From the Newton's law,

→ $F_{app} = (\frac{F_{app}}{m_A+m_B} )a$

or,

→ $a = \frac{F_{app}}{(m_A+m_B)}$

Bu substituting the values, we get

→ $= \frac{100}{9+2}$

→ $= \frac{100}{11}$

→ $9.10 \ m/s^2$

We can see that between the two boxes, the action-reaction pair exist.

then,

→ $F_{action-reaction} = m_b \ a$

→ $=2\times 9.10$

→ $= 18.2 \ N$ (magnitude)

Thus the above solution is appropriate.

Learn more about the magnitude here:

brainly.com/question/13545862

7 0

2 years ago

According to information found in an old hydraulics book, the energy loss per unit weight of fluid flowing through a nozzle conn

suter [353]

This question is incomplete, the complete question is;

According to information found in an old hydraulics book, the energy loss per unit weight of fluid flowing through a nozzle connected to a hose can be estimated by the formula; h= (0.04 to 0.09)(D/d)⁴V²/2g

where h is the energy loss per unit weight, D the hose diameter, d the nozzle tip diameter, V the fluid velocity in the hose, and g the acceleration of gravity.

Do you think this equation is valid in any system of units

Answer:

YES, the equation is a general equation that is valid in any system of units

Explanation:

Given the data in the question;

h = (0.04 to 0.09)(D/d)⁴ × $\frac{V^{2} }{2g}$

[ N.m/N ] = (0.04 to 0.09) ( m/m)² × (m²/s²)1/2 × (s²/m)

[ N.L/N ] = (0.04 to 0.09) ( L⁴/L⁴) × (L²/T²)1/2 × (T²/L)

∴ [ L ] = (0.04 to 0.09) [L]

So as each term in the equation must have the same dimensions, the constant term (0.04 to 0.09) must be without dimension.

Therefore, YES, the equation is a general equation that is valid in any system of units

5 0

2 years ago