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miskamm [114]
3 years ago
5

How many grams of calcium hydroxide must react to give 3.09 g of Ca3(PO4)2?

Chemistry
1 answer:
emmainna [20.7K]3 years ago
7 0
Molar mass:

Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol

Mole ratio:

<span>2 Na</span>₃<span>PO</span>₄<span> + 3 Ca(OH)</span>₂<span> = Ca</span>₃<span>(PO</span>₄<span>)</span>₂<span> + 6 NaOH
</span>
3 x 74.093 g Ca(OH)₂ ----------- 310.17 g Ca₃(PO₄)₂
            ?? g Ca(OH)₂ ----------- 3.09 g Ca₃(PO₄)₂

Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17

Mas of Ca(OH)₂ = 686.84211 / 310.17

= 2.214 g of Ca(OH)₂

hope this helps!



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