Answer:
The line voltage of the three phase network is 346.41 V
Explanation:
Star Connected Load
Resistance, R₁ = R₂ = R₃ = 18 Ω
For a star connected load, the line current = the phase current, that is we have
Whereby the the voltage across each resistance = 
is given by the relation;
= 
× R
Hence;
= = × R = 25 × 8 = 200 V
Therefore we have;
The line voltage, 
= √3 × = √3 × 200 = 346.41 V.
Hence, the line voltage of the three phase network = 346.41 V.
Answer:
(C) calcNewPrice(oldPrice, &newPrice);
Explanation:
It's a void function so there's no return value, however they wanted to change a value. The only way to do that is to pass in an address of the variable into the function, and deference it and store the new data there.
D) O Water - Based Is the 1000000000000000000% correct answer
(
, 
, 
) = (3, -6, 3)
<u>Explanation:</u>
Given data,
5 packets are delivered by channel, which was randomly taken.
0(P(0)), 1(P(1)), 2(P(2)), 3(P(3)), 4(P(4))
Bob receives are
(0,3) (1,0) (2,3) (3,0) (4,3)
P(0) = 3
P(1) = 0
P(2) = 3
P(3) = 0
P(4) = 3
The given equation is
Solution:
= 3
= 3
= - 3
= 3
= 0
= 0
= 3
= 0
From P(1) and P(2)
-3 + = 0
= 3
= -6
(, , ) = (3, -6, 3)
