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Vitek1552 [10]
3 years ago
5

Exhaust gases entering a convergent nozzle have a total pressure (Pt) of 200 kPa and total temperature (Tt) of 800 K. The gases

exit the nozzle into ambient air at a static pressure (Po) of 101.3 kPa. Assuming that y 1.33 and R-287 J/(kg.K), determine the critical pressure ratio.
Engineering
2 answers:
madam [21]3 years ago
5 0

Answer:

critical pressure ratio = 108.07 k pa

Explanation:

Pt = 200 k Pa

Tt = 800 k

Po = 101.3 k Pa

y = 1.33

R = 287 J/(kg.k)

critical pressure ratio ( Pc )

\frac{Pc}{Pt} = (\frac{2}{y+1})^{\frac{y}{y-1} }  ------- equation 1

Pt given as 200 k Pa

Y = 1.33

back to equation 1

\frac{Pc}{Pt} = (\frac{2}{1.33 + 1})^{\frac{1.33}{1.33 - 1} }

Pc = 200 * 0.5404 = 108.07 k pa

Pavlova-9 [17]3 years ago
4 0

Answer:

0.351

Explanation:

n=1/(γ−1) = 1/ (1.33-1)= 3.03

critical pressure ratio

p_2/p_1 = \frac{2}{n+1} ^{(\frac{n}{n-1} )}\\\\=  \frac{2}{3.03+1} ^{(\frac{3.03}{3.03-1} )}\\\\= 0.496^{1.493}\\\\= 0.351

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zzz [600]

Answer:

Heat flux of CO₂ in cgs

                 = 170.86 x 10⁻⁹ mol / cm²s

SI units

       170.86 x 10⁻⁸ kmol/m²s  

Explanation:

4 0
3 years ago
Using the results of the Arrhenius analysis (Ea=93.1kJ/molEa=93.1kJ/mol and A=4.36×1011M⋅s−1A=4.36×1011M⋅s−1), predict the rate
uysha [10]

Answer:

k = 4.21 * 10⁻³(L/(mol.s))

Explanation:

We know that

k = Ae^{-E/RT} ------------------- euqation (1)

K= rate constant;

A = frequency factor = 4.36 10^11 M⁻¹s⁻¹;

E = activation energy = 93.1kJ/mol;

R= ideal gas constant = 8.314 J/mol.K;

T= temperature = 332 K;

Put values in equation 1.

k = 4.36*10¹¹(M⁻¹s⁻¹)e^{[(-93.1*10^3)(J/mol)]/[(8.314)(J/mol.K)(332K)}

k = 4.2154 * 10⁻³(M⁻¹s⁻¹)

here M =mol/L

k = 4.21 * 10⁻³((mol/L)⁻¹s⁻¹)

 or

k = 4.21 * 10⁻³((L/mol)s⁻¹)

or

k = 4.21 * 10⁻³(L/(mol.s))

3 0
3 years ago
You are traveling upstream on a river at dusk. You see a buoy with the number 5 and a flashing green light . What should you do?
nalin [4]

Answer:

please give brainliest my brother just got the corona virus

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this is my brothers account he wants to get 5 brainliest

8 0
3 years ago
Koch traded Machine 1 for Machine 2 when the fair market value of both machines was $60,000. Koch originally purchased Machine 1
Mariana [72]

Answer:

Koch's adjusted basis in machine 2 after the exchange is $60,000

Explanation:

given data

fair market value = $60,000

originally purchased Machine 1 = $76,900

Machine 1 adjusted basis = $40,950

Machine 2 seller purchase = $64,050

Machine 2 adjusted basis = $55,950

solution

As he exchanged machine for another at $60,000

and this exchanged in fair market

so adjusted basis =  $50,000

Adjusted basis is the price of the item that affects the factors that are considered price. These factors usually include taxes, depreciation value, and other costs of acquiring and maintaining a given item. Adjusted basis is important so the right amount to sell

Adjusted basis increases when a person deducts expenses from factor taxes and operating statements

so Koch's adjusted basis in machine 2 after the exchange is $60,000

3 0
3 years ago
Indicate the correct statement about the effect of Reynolds number on the character of the flow over an object.
sergeinik [125]

Answer:

If Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.

Explanation:

Reynolds number is an important dimensionless parameter in fluid mechanics.

It is calculated as;

R_e__N} = \frac{\rho vd}{\mu}

where;

ρ is density

v is velocity

d is diameter

μ is viscosity

All these parameters are important in calculating Reynolds number and understanding of fluid flow over an object.

In aerodynamics, the higher the Reynolds number, the lesser the viscosity plays a role in the flow around the airfoil. As Reynolds number increases, the boundary layer gets thinner, which results in a lower drag. Or simply put, if Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.

5 0
3 years ago
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