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Answer:
A1 = 3A, A2 = 1.5A
Effective resistance = 2Ω
Explanation:
When the switch is closed, the voltage across each resistor is 6V, so the current through it (A2) is ...
A2 = 6V/(4Ω) = 1.5A
There are two parallel paths, each with that current, so the current from the battery is ...
A1 = A2 +A2 = 1.5A +1.5A = 3.0A
Then the effective resistance is ...
Reff = 6V/(3.0A) = 2.0Ω
The solution to the circuit is ...
A1 = 3A, A2 = 1.5A
Effective resistance = 2Ω
Answer:
final volume the balloon occupy in instant before it burst is 4.634 L
Explanation:
given data
helium filled V1 = 2 L
initially pressure P1 = 1.25 atm
finally pressure P2 = 410 mmHg
1 atm = 760 mmHg
to find out
at what volume the balloon occupy in instant before it burst
solution
we have given
760 mmHg = 1atm
and 1 mmHg = 1/760
so 410mmHg = 410/760 atm
so that final pressure is = 410/760 atm
we use here Boyle's Law that is
Boyle's law states that "the volume of an ideal gas is inversely proportional to the pressure of the gas at constant temperatures"
so P ∝ 1/V
P1V1 = P2V2
V2 = P1V1 / P2
put all value
V2 = 1.25 (2) / (410/760)
V2 = 2.5 / 0.53947 = 4.634
so final volume the balloon occupy in instant before it burst is 4.634 L
Answer:
Explanation:
Angular acceleration is defined as the variation of angular speed with respect to time:
The relation between the angular speed and the linear speed is given by:
Replacing (2) in (1):
We need to convert 
to 
:
Recall that:
Replacing:
Answer:
d. 100.0 J
Explanation:
To solve this problem we must use the theorem of work and energy conservation. This tells us that the mechanical energy in the final state is equal to the mechanical energy in the initial state plus the work done on a body. In this way we come to the following equation:
E₁ + W₁₋₂ = E₂
where:
E₁ = mechanical energy at state 1. [J] (units of Joules)
E₂ = mechanical energy at state 2. [J]
W₁₋₂ = work done from 1 to 2 [J]
We have to remember that mechanical energy is defined as the sum of potential energy plus kinetic energy.
The energy in the initial state is zero, since there is no movement of the hockey puck before imparting force. E₁ = 0.
The Work on the hockey puck is equal to:
W₁₋₂ = 100 [J]
100 = E₂
Since the ice rink is horizontal there is no potential energy, there is only kinetic energy
Ek = 100 [J]
It can be said that the work applied on the hockey puck turns into kinetic energy
The answer is <span>Qualitative</span>
