Answer: a. +2, cation and magnesium ion .
b. -1, anion, chloride
c. -2, anion, oxide
d. +1. cation , potassium ion
Explanation:
When an atom accepts an electron negative charge is created on atom and is called as anion.
When atom loses an electron positive charge is created on atom and is called as cation.
Magnesium (Mg) with atomic number of 12 has electronic configuration of 2,8,2 and thus it can lose 2 electrons to form 
cation and becomes magnesium ion.
Chlorine (Cl) with atomic number of 17 has electronic configuration of 2,8,7 and thus it can gain 1 electron to form 
anion and becomes chloride.
Oxygen (O) with atomic number of 8 has electronic configuration of 2,6 and thus it can gain 2 electrons to form 
anion and becomes oxide.
Potassium (K) with atomic number of 19 has electronic configuration of 2,8,8,1 and thus it can lose 1 electron to form 
cation and becomes potassium ion.
Answer:
Your question is half unfinished, regarding the chromium III oxide the correct option that expresses the inorganic formula of said compound is "A"
Explanation:
In the reaction an initial salt reacts giving as product water vapor, nitrogen gas and an oxide that is chromium oxide.
Chromium oxide is an oxide that adopts the structure of corundum, compact hexagonal. It consists of an anion oxide matrix with 2/3 of the octahedral holes occupied by chromium. Like corundum, Cr2O3 is a tough, brittle material.
It is used as a pigment, green in color.
Answer:
Atomic number
Explanation:
Atomic number is the number of protons, and therefore also the total positive charge, in the atomic nucleus. The Rutherford–Bohr model of the hydrogen atom (Z = 1) or a hydrogen-like ion (Z > 1).
Heat energy released : 167.2 kJ
<h3>Further explanation</h3>
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
m = 2000 g
c = 4.18 J/ g ° C
∆t = 20 ° C
Answer:
Mass of PbS = 9.26 g
Explanation:
Data Given :
mass of H₂S = 5.00 g
mass of PbS = ?
Reaction Given:
Pb(CH₃COO)₂ + H₂S ----→ PbS + CH₃COOH
Solution:
Balance the equation:
Pb(CH₃COO)₂ + H₂S ----→ PbS + 2CH₃COOH
Now Look for the number of moles of H₂S and PbS meta
Pb(CH₃COO)₂ + H₂S ----→ PbS + 2CH₃COOH
1 mol 1 mol
So,
1 mole of H₂S combine with excess (unlimited) supply of Pb(CH₃COO)₂ and produce 1 moles of PbS
Now Convert moles to mass for which we have to molar masses of H₂S and PbS
Molar mass of H₂S = 2 + 32 = 43 g/mol
Molar mass of PbS = 31 + 32 = 63 g/mol
Pb(CH₃COO)₂ + H₂S -------→ PbS + 2CH₃COOH
1 mol (34 g/mol) 1 mol (63 g/mol)
34 g 63 g
So,
34 g of H₂S produces 63 grams of PbS.
Now
What mass of silver is produced from 5 g of H₂S
Apply unity formula
34 g of H₂S ≅ 63 g of PbS
5 g of H₂S ≅ X g of PbS
By doing cross multiplication
Mass of PbS = 63 g x 5 g / 34 g
Mass of PbS = 9.26 g
