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polet [3.4K]
3 years ago
13

An 85-kg rock climber, when reaching the summit, built up 250,000 J of gravitational potential energy. How high did the climber

go?
Physics
2 answers:
Elodia [21]3 years ago
4 0

Answer: 300 m

Explanation:

A body possesses gravitational potential energy due to virtue of its height above the surface. It is measured in Joules. it is given by:

G.P.E = m g h

where, m is the mass, g is the acceleration due to gravity and h is the height.

Given: m = 85 kg

G.P.E = 250,000 J

g = 9.8 m/s²

⇒ h = (G.P.E}/ mg

⇒h = (250,000) / ( 85 × 9.8) = 300 m.

The climber climbed 300 m high.

Vesna [10]3 years ago
3 0

It's 300! I just got it correct:)

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Delvig [45]

Answer:

The amount of Potential Energy lost in the form of Thermal Energy is equal to 41.64 MJ.

Explanation:

mass of the cart and passengers = m = 3.5*10⁴ kg

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v = 10 ms⁻¹

At the top position the Total energy of the ride is in the form of potential energy given as:

P.E = mgh

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At the bottom of the drop, all the Potential Energy will be converted into K.E as the ride develops speed given as:

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= 41639500 J

= 41.64 M J approx             M J = mega joule = 10⁶ J

7 0
3 years ago
if a 5-kg bowling ball is projected upward witha velocity of 2.0 m/s, then what is the recoil velocity of the Earth(mass=6.0×10^
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by the concept of momentum conservation we can say

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v_2 = \frac{5*2}{6 * 10^{24}}

v_2 = 1.67 * 10^{-24} m/s

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