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Dmitriy789 [7]
3 years ago
5

Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

Physics
1 answer:
tester [92]3 years ago
6 0

Answer: 40\ N/C

Explanation:

Given

Magnitude of charge is q=0.5\ C

Force experienced is F=20\ N

Electric field intensity is the electrostatic force per unit charge

\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C

Thus, the electric field intensity is 40\ N/C

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