Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

Physics

1 answer:

tester [92]3 years ago

6 0

Answer: $40\ N/C$

Explanation:

Given

Magnitude of charge is $q=0.5\ C$

Force experienced is $F=20\ N$

Electric field intensity is the electrostatic force per unit charge

$\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C$

Thus, the electric field intensity is $40\ N/C$

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