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3 years ago

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1 ) Starting from rest, a toy rocket accelerates at 12 m/sec/sec for exactly 4.0 seconds. It reaches 48 m/sec. Find the distance

moved.

1 answer:

dusya [7]3 years ago

3 0

Displacement equals (Velocity times Time) plus half times the (acceleration times time squared). =. (48 * 4) + 1/2 * (12 *12^2) = 288meters

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The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares

KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, $\theta_1=47.7^{\circ}$

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Using Snell's law for air liquid interface as :

$n_1\ sin\theta_1=n_2\ sin(90)$

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$n_1=\dfrac{1}{sin(47.7)}$

$n_1=1.35$

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

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3 years ago

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uysha [10]

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3 years ago

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Alexeev081 [22]

Answer:

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Explanation:

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And its direction is

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3 years ago

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Answer:

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Explanation:

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3 years ago

Natalija [7]

Answer:

Explanation:

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hope this helps

plz mark it as brainliest

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3 years ago

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