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3 years ago

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1 ) Starting from rest, a toy rocket accelerates at 12 m/sec/sec for exactly 4.0 seconds. It reaches 48 m/sec. Find the distance

moved.

1 answer:

dusya [7]3 years ago

3 0

Displacement equals (Velocity times Time) plus half times the (acceleration times time squared). =. (48 * 4) + 1/2 * (12 *12^2) = 288meters

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Answer:

8 km/h²

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a = v-u/t

v is final velocity, u is initial velocity

a = 40-0/5

a = 8.0 km/h²

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3 years ago

Two technicians are discussing testing MAP sensors. Technician A says that the MAP sensor should be replaced if anything comes o

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4 years ago

The standard unit for measuring volume is the _____. milliliter liter deciliter cubic centimeter

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Cubic centimeter is the answer

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4 years ago

Read 2 more answers

A rock is dropped from a vertical cliff. The rock takes 3.00 s to reach the ground below the cliff. A second rock is thrown vert

Phantasy [73]

Answer:

Velocity v= 12.25 $\frac{m}{s}$

Explanation:

The first rock dropped give the distance Y in meters

$Y_{f}=Y_{o}+v_{o}*t +\frac{1}{2}*a*t^{2}\\ Y_{f}=\frac{1}{2}* 9.8 \frac{m}{s^{2} }* 3^{2} \\Y_{f}=44.1 m$

Now the motion of the second rock the time change so to know the velocity

$Y_{f}= Y_{o} +v_{o}*t +\frac{1}{2}*a *t^{2} \\v_{o}*t= -Y_{f} +\frac{1}{2} *a*t^{2} \\v_{o} =\frac{-44.1 +0.5 * 9.8* s^{2} }{2} \\v_{o}= 12.25 \frac{m}{s}$

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3 years ago

A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is fo

Alex787 [66]

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

$R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)$

At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

$R = \rho* \frac{L}{A} (2)$

The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

$A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)$

Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

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ρ = 1.6*10⁻⁸ Ω/m

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3 years ago