Answer:
q = 4.5 nC
Explanation:
given,
electric field of small charged object, E = 180000 N/C
distance between them, r = 1.5 cm = 0.015 m
using equation of electric field
k = 9 x 10⁹ N.m²/C²
q is the charge of the object
now,
q = 4.5 x 10⁻⁹ C
q = 4.5 nC
the charge on the object is equal to 4.5 nC
Answer:
0.98°
Explanation:
First we find the refracting angle of orange in water
Which is given as
စr= sin^-1. ( 1.456 sin60°/1.33)
= 71.2°
Then that of violet in water
စv=sin^-1. ( 1.468sin60°/1.342)
= 72.3°
So angle between boths colours is the difference
71.2- 72.3= 0.98°
By using the same frequency channel.
Resistance = (potential difference) / (current) = 120V / 0.5A = <em> 240 ohms .</em>
