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VLD [36.1K]
2 years ago
13

What part causes the disc brake caliper piston to retract when the brakes are released?

Physics
1 answer:
Orlov [11]2 years ago
3 0
The part that causes the disc caliper piston to retract when the brakes are released is the square-cut O-ring.
The square cut seal is the most important part of a disc brake caliper, for keeping the brake behind the piston so that when you step on the brake pedal, it releases a pressure that applied to the piston which in return applies the pad to the rotor.
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A bullet is fired horizontally with an initial velocity of 144.7 m/s from a tower 11 m high. if air resistance is negligible, wh
scoundrel [369]
H = 11 m, the vertical distance that the bullet falls.
Initial vertical velocity  = 0
Horizontal velocity  = 144.7 m/s

The time, t, taken to fall 11 m is given by
(1/2)*(9.8 m/s²)*(t s)² = (11 m)
4.9t² = 11
t = 1.4983 s

If aerodynamic resistance is ignored, the horizontal distance traveled before the bullet hits the ground is
d = (144.7 m/s)*(1.4983 s) = 216.8 m

Answer: 216.8 m
6 0
2 years ago
Ice caps at the north and south poles are very reflective the ice reflects light and heat rather than absorbing it. If global wa
PolarNik [594]
The way you described it, a small change will cause a bigger change.
That's Positive feedback.
5 0
2 years ago
What is the weight of a 24.52kg Television dropped on pluto(acceleration of 0.59m/s/s)?
jolli1 [7]
W=ma=24.52*0.59 = ...

6 0
3 years ago
Read 2 more answers
A car moving at 60 mph slams on its brakes to stop before hitting a deer. Another identical car traveling at 60 mph slows to a s
ankoles [38]

Happy Holidays!

Recall that:

Impulse = Change in Momentum = mass × change in velocity

Since both cars are identical and have the same initial velocity of 60 mph, them breaking to a stop means that they both experience the same change in velocity.

Thus, both of the cars' impulses are equal.

8 0
2 years ago
an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
Andrei [34K]

amount of work done is 5880 J

Given:

mass of object = 50kg

Final height = 20m

initial height = 8m

To Find:

amount of work done

Solution:

work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

The work done by gravity is given by the formula,

W = mgh

W = 50 x 9.8 x ( 20-8)

= 5880 J

So the work done is 5880 J

Learn more about Work done here:

brainly.com/question/25239010

#SPJ4

7 0
1 year ago
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