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3 years ago

What part causes the disc brake caliper piston to retract when the brakes are released?

1 answer:

3 0

The part that causes the disc caliper piston to retract when the brakes are released is the square-cut O-ring.
The square cut seal is the most important part of a disc brake caliper, for keeping the brake behind the piston so that when you step on the brake pedal, it releases a pressure that applied to the piston which in return applies the pad to the rotor.

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Water flows on the inside of a steel pipe with an ID of 2.5 cm. The wall thickness is 2 mm, and the convection coefficient on th

Hatshy [7]

Answer:

U = 11.67 W/m² °C

Explanation:

Inner diameter, d = 2.5 cm = 0.025 m

Thickness of the wall, t = 2 mm = 0.002 m

thus, the outer diameter, D = d + 2t = 0.025 + 2 x 0.002 = 0.029 m

$h_i =500 W/m^2.^oC$

$h_0 =12 W/m^2.^oC$

Now, based on outside convection heat transfer

we have

$\frac{1}{UA_o}=\frac{1}{h_iA_i}+\frac{1}{h_oA_o}$

on rearranging, we get

$\frac{1}{U}=\frac{1}{h_i}\frac{A_o}{A_i}+\frac{1}{h_o}$

where, $A_i\ \textup{and}\ A_o$ are the perimeter respective to inner and and outer diameter

on substituting the values, we get

$\frac{1}{U}=\frac{1}{500}\frac{0.029^2}{0.025}+\frac{1}{12}$

U = 11.67 W/m² °C

6 0

4 years ago

You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 690.0 kg and was tra

kirza4 [7]

Answer:

115 km/h

Explanation:

$m_1$ = Mass of car A = 690 kg

$m_2$ = Mass of car B = 520 kg

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration

u = Initial velocity

v = Final velocity

$a=\mu g\\\Rightarrow a=0.75\times 9.81\\\Rightarrow a=7.3575\ m/s^2$

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 7.3575\times 6+0^2}\\\Rightarrow v=9.396\ m/s$

$m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow u_1=\frac{(m_1 + m_2)v-m_2u_2}{m_1}\\\Rightarrow u_1=\frac{(690+520)9.396-520\times -\frac{74}{3.6}}{690}\\\Rightarrow u_1=31.96\ m/s$

Converting to km/h

$31.96\times 3.6=115.056\ km/h$

Initial velocity of car A = 115 km/h

7 0

3 years ago

Si dejamos caer un objeto desde una gran altura, ¿será que tiene siempre la misma velocidad

olga55 [171]

La respuesta es si.

8 0

4 years ago

Read 2 more answers

Calculate the volume of this regular solid. A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.

Kryger [21]

Answer:

The volume of the cylinder is $653.71\ \text{cm}^3$

Explanation:

Given that,

The height of the cylinder is 13 cm

Radius of the cylinder is 4 cm

We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

$V=\pi r^2 h\\\\V=\dfrac{22}{7} \times (4)^2 \times 13\\\\V=653.71\ \text{cm}^3$

So, the volume of the cylinder is $653.71\ \text{cm}^3$

4 0

3 years ago

Read 2 more answers

Circuit A in a house has a voltage of 208 V and is limited by a 40.0-A circuit breaker. Circuit B is at 120.0 V and has a 20.0-A

Setler79 [48]

Given Information:

Voltage of circuit A = Va = 208 Volts

Current of circuit A = Ia = 40 Amps

Voltage of circuit B = Vb = 120 Volts

Current of circuit B = Ib = 20 Amps

Required Information:

Ratio of power = Pa/Pb = ?

Answer:

Ratio of power = Pa/Pb = 52/15

Explanation:

Power can be calculated using Ohm's law

P = VI

Where V is the voltage and I is the current flowing in the circuit.

The power delivered by circuit A is

Pa = Va*Ia

Pa = 208*40

Pa = 8320 Watts

The power delivered by circuit B is

Pb = Vb*Ib

Pb = 120*20

Pb = 2400 Watts

Therefore, the ratio of the maximum power delivered by circuit A to that delivered by circuit B is

Pa/Pb = 8320/2400

Pa/Pb = 52/15

4 0

3 years ago