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VLD [36.1K]
2 years ago
13

What part causes the disc brake caliper piston to retract when the brakes are released?

Physics
1 answer:
Orlov [11]2 years ago
3 0
The part that causes the disc caliper piston to retract when the brakes are released is the square-cut O-ring.
The square cut seal is the most important part of a disc brake caliper, for keeping the brake behind the piston so that when you step on the brake pedal, it releases a pressure that applied to the piston which in return applies the pad to the rotor.
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What is a conservative force?
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A conservative force is a force with the property that the total work done in moving a particle between two points is independent of the path taken Equivalently if a particle travels in a closed loop the total work done by a conservative force is zero

Explanation:

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3 years ago
Timmy drove 2/5 of a journey at an average speed of 20 mph.
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4hr

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What is the speed of a wave frequency of 300hz and a wavelength of 25M
tia_tia [17]

Answer:

7500 m/s

Explanation:

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2 years ago
If the velocity of an object is zero at one instant, what is true about the acceleration of that object
Charra [1.4K]

Answer:

I. The acceleration could be positive.

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III. The acceleration could be negative.

Explanation:

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

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Velocity = \frac{distance}{time}

If the velocity of an object is zero at one instant, then the acceleration of that object may have the following characteristics;

I. The acceleration could be positive.

II. The acceleration could be zero.

III. The acceleration could be negative.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

8 0
2 years ago
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