(a) the weight of the fish is:
and this is the force that stretches the spring by
. So, we can use Hook's law to find the constant of the spring:
(b) The fish is pulled down by 2.8 cm = 0.028 m more, so now the total stretch of the spring is
But this is also the amplitude of the new oscillation, because this is the maximum extension the spring can get, so A=6.5 cm.
The angular frequency of oscillation is given by:
and so the frequency is given by
More people walk to school or work hope this helps
Answer:
727.67 km
Explanation:
Sine they have Same distance D
distance = speed * time
D = 5.08t
D = 8.3312(t+55.9)
so
5.08t = 8.3312(t+55.9) t in
3.2512t = 465.71
t = 143.2s
Subtitute t
D=5.08 t
= 5.08 × 143.2
= 727.67km
Answer:
0.333 m/s
Explanation:
avg speed= (total distance)/(total time)
10m/30s
0.333 m/s
Answer:
a) 3.0 x 10¹⁰ J
b) 7.75 x 10³ m/s
Explanation:
a)
ΔV = potential difference between cloud and the ground = 1.0 x 10⁹ Volts
Q = Amount of charge transferred = 30 C
ΔU = Change in energy transferred
Change in energy transferred is given as
ΔU = Q ΔV
ΔU = (30) (1.0 x 10⁹)
ΔU = 3.0 x 10¹⁰ J
b)
v₀ = initial speed of the automobile = 0 m/s
v = final speed of the automobile = ?
m = mass of automobile = 1000 kg
Using conservation of energy
ΔU = (0.5) m (v² - v₀²)
3.0 x 10¹⁰ = (0.5) (1000) (v² - 0²)
v = 7.75 x 10³ m/s