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Georgia [21]
3 years ago
7

Which statement best explains the relationship between an area's geography and the temperature of its surface water?

Chemistry
1 answer:
Darina [25.2K]3 years ago
6 0

B.) Areas at low latitudes have the warmest water because they receive the most direct sunlight.

Explanation:

The most accurate statement of all that shows the relationship between an area's geography and temperature of its surface water is that areas at low latitudes have the warmest water because they receive the most direct sunlight.

Areas at low latitude are close to the equator. Areas at high latitude tends towards the pole.

  • At the equator, the sun is over head and it beams direct sunlight to all parts here.
  • This makes ocean water to be at a high temperature in low latitude.
  • At high latitude, the ocean surface receives diffused sunlight.
  • This makes them less warm compared to areas around the equator at low latitude.

learn more:

latitude brainly.com/question/4504954

#learnwithBrainly

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The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C
Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})

ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})

1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})

ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})

1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})

T₂=371.77 K= 98.62 °C

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The smallest unit of an element that retains all the characteristics of that element is called a(n)
Maksim231197 [3]
<span>The smallest unit of an element that retains all the characteristics of that element is called an A. atom.
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3 years ago
g A mass spectrum. The peak at mass 100 has a 8% relative abundance. THe peak with mass 85 has a 40% abundance. The peak at 71 h
Sati [7]

Answer:

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REY [17]

hey mate here is ur answer

solution

mass{m}=3 gram

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volume{v}=16cm

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density=m/v

           =3/1000÷16/100

           =3/160

            =0.01875kg/m3

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