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lesya692 [45]
3 years ago
10

How many atoms are here in the following?

Chemistry
1 answer:
Elina [12.6K]3 years ago
6 0

Answer:

A. 6N

B. 4H, 2O

C. 4H, 4N, 12O

D. 2Ca, 4O, 4H

E. 3Ba, 6Cl, 18O

F. 5Fe, 10N, 30O

G. 12Mg, 8P, 32O

H. 4N, 16H, 2S, 8O

I. 12Al, 18Se, 72O

J. 12C, 32H

I am 90% sure this is correct

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The electron configuration of a neutral atom is 1s22s22p63s2. Write a complete set of quantum numbers for each of the electrons.
Pavlova-9 [17]

Answer:

The four quantum number for each electron will be:

1s^{2}

n=1;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2s^{2}

n=2;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2p^{6}

n=1;l=1;\\m=+1,0.-1 \\s=+\frac{1}{2}/-\frac{1}{2}

3s^{2}

n=3;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

Explanation:

As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.

Number of electrons =12

Atomic number = 12

Element : Magnesium

The principal shell is represented by "n"

i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0

The two electrons in s subshell will have either plus half or minus half spin quantum number

ii) for "p" subshell the value for l =1

thus m = 0 or +1 or -1

The two electrons in each orbital will have either plus half or minus half spin quantum number

8 0
3 years ago
Use the equation n2 + 3h2=2nh3 if 8.0g N2 react, how many grams of NH3 will be produced
Eduardwww [97]

the balanced equation for the formation of ammonia is

N₂ + 3H₂ ---> 2NH₃

molar ratio of N₂ to NH₃ is 1:2

mass of N₂ reacted is 8.0 g

therefore number of N₂ moles reacted is - 8.0 g / 28 g/mol = 0.286 mol

according to the molar ratio,

1 mol of N₂ will react to give 2 mol of NH₃, assuming nitrogen is the limiting reactant

therefore 0.286 mol of N₂ should give - 2 x 0.286 mol = 0.572 mol of NH₃

therefore mass of NH₃ formed is - 0.572 mol x 17 g/mol = 9.72 g

a mass of 9.72 mol of NH₃ is formed

6 0
3 years ago
A 2.75 kg sample of a substance occupies a volume of 250.0 cm3. Find its density in g/cm3.
satela [25.4K]
Density is 0.011 g/cm3.
5 0
3 years ago
Read 2 more answers
A coffee-cup calorimeter initially contains 125 g water at 24.28C. Potassium bromide (10.5 g), also at 24.28C, is added to the w
iren2701 [21]

Answer:

The solution is given below

Explanation:

Heat, q= mc∆T

q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C

q=  -1619.75J

NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.

Enthalpy Change, ∆H = 1619.75 7/ 10.5 g

                                     = 154.26 J/g

No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr

                                =10.5g/119gmol-1

                                =0.088 mol

∆H= 1619.75 J/ 0.088 mol

      = 18.41 kJ/mol  

6 0
3 years ago
True or false weight is affected by gravity
bazaltina [42]

true, in a stronger gravitational field the weight will be larger.

6 0
3 years ago
Read 2 more answers
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