Each period corresponds to a principal energy level.
Answer:
Explanation:
Mixing Ammonia gas into a solution of Copper(II) Sulfate will give Ammonium Sulfate and a precipitate of Copper(II) Hydroxide (Cu(OH)₂). The Ksp of Cu(OH)₂ is published => 2.2 x 10⁻²². Such gives a solubility* of the Cu(OH)₂ to be ~1.77 x 10⁻⁷M => [Cu⁺²] ~1.77 x 10⁻⁷M and [OH⁻] = 2(1.77 x 10⁻⁷)M = 3.53 x 10⁻⁷M. The reaction of Ammonium Hydroxide and Copper(II) Sulfate will generate 1 x 10⁻⁴ mole Cu(OH)₂ as a precipitate but only 1.77 x 10⁻⁷ mole of the hydroxide will remain in 1 Liter of solution b/c of extreme limited solubility.
*Solubility of 1:2 ionization ratio salts = CubeRt(Ksp/4).
Answer:
Passive Transport
Explanation:
The three examples of passive transport are
Diffuison
Osmosis
facilated diffuison
So the answer can be A or B
The answer is 0.0171468704904. We assume you are converting between moles Mg(OH)2 and gram. This compound is also known as Magnesium Hydroxide. 1 mole<span> is equal to </span>1 moles<span> Mg(OH)2, or 58.31968 grams.</span>
Answer: Dipole moment
Explanation: Dipole moment is defined as product of magnitude of the charge and the distance between the charges of equal magnitude and opposite sign is called as dipole moment.
S.I unit of dipole moment is Debye (D).
Debye was defined as the dipole moment resulting from two charges of opposite sign but an equal magnitude of stat coulomb (generally called e.s.u. (electrostatic unit) which were separated by 1 angstrom.(1 angstrom cm)