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Harlamova29_29 [7]
3 years ago
14

How does the periodic table indicate the number of valence electrons element has?

Chemistry
1 answer:
Yuri [45]3 years ago
7 0

option A.

The number of valence electrons of an element can be determined by the periodic table group (vertical column) in which the element is categorized

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A jet is goes from 180km/s to 139km/s in 22 seconds. What is it's acceleration?
jeyben [28]
180 km/s V= 25



explanation: i had the same assignment
5 0
3 years ago
The atoms of a solid aluminum can are close together, vibrating in a rigid structure. if the can is warmed up on a hot plate,
Alexxx [7]

Answer:the atoms of a solid aluminium can are close together vibrating in a rigid structure if the can is warmed up on a hot plate

Explanation:

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3 years ago
According to the Law of Conservation of Mass, how much water is produced if 22.5 g of
nadezda [96]

Answer: The amount of water produced is 9.3 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CH_4+2O_2\rightarrow CO_2+2H_2O

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4 0
3 years ago
True or false? the parent material has a large influence on a soil's physical and chemical properties.
enot [183]

Answer:

true, true, true, and false

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6 0
3 years ago
Read 2 more answers
Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
bearhunter [10]

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles

The balanced chemical equuation is:

4Al+3O_2\rightarrow 2Al_2O_3  

According to stoichiometry :

4 moles of Al produce == 2 moles of Al_2O_3

Thus 0.556 moles of Al will produce=\frac{2}{4}\times 0.556=0.278moles  of Al_2O_3

Mass of Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0
2 years ago
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