A single-phase inductive load draws a 10 MW at 0.6 power factor lagging. Calculate the reactive power of a capacitor to be conne
cted in parallel with the load to raise the power factor to 0.89. Type your answer on the box, and make sure your answer have two decimal digits and the correct sign.
1 answer:
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Answer:
LAOD = 6669.86 N
Explanation:
Given data:
width
thickness
crack length 2c = 0.5 mm at centre of specimen
stress intensity factor = k will be
we know that
[c =0.5/2 = 2.5*10^{-4}]
K = 0.1724 Mpa m^{1/2} for 1000 load
if then load will be
LAOD = 6669.86 N