Answer:
Average speed of the car = 16.53 m.s
Explanation:
For first 5 seconds:
As the car starts from rest, so the initial speed of the car, u=0
Acceleration, a= 4 m/s^2
So, the final speed (speed at time, t=5 second)
v=u+at
v=0 + 4 x 5 = 20 m/s
Distance covered,
s=50 m
As the car maintained the constant speed of 20 m/s for the next 10 seconds.
Distance traveled in 10 seconds, d=20 x 10 =200 m
For the last 4 seconds:
The car slows down at the rate of 2.0 m / s ^ 2 from the speed of 20 m/s.
As the car slows down, so the acceleration will be negative, i.e a=-2 m/s^2
s=80-16=64 m.
Considering all three cases, the total distance covered=
=50+200+64=314 m
Total time= 5+10+4=19 s
So, the averate peed= Totat distance covered / total time taken
=314/19=16.53 m/s
Answer:
ACCELARATION
The slope of a velocity graph represents the acceleration of the object. So, the value of the slope at a particular time represents the acceleration of the object at that instant.
Explanation:
pls mark as brailiest
Both of them are substances which comes between the path of electricity but the difference is that one let the electricity to pass that is conductor and other acts as breaker in the connection which is a insulator.
Acceleration = v-u/t
= (45-30)/15
= 1 km/h
Distance = ut + 1/2 at^2
s = [30 x 15] + 1/2 x 1 x 15^2
= 562.5 km
Hope this helps