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lana [24]
3 years ago
15

Approximately how much of the world’s oil and natural gas reserves are believed to be in the arctic? View Available Hint(s) Appr

oximately how much of the world’s oil and natural gas reserves are believed to be in the arctic? 1/8 1/4 1/2 3/4 All of the world’s oil and natural gas reserves are in the arctic.
Chemistry
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

1/4 or 25%

Explanation:

The Arctic region of the earth refers to that part of the earth around the north pole region. Hence, when we are talking about latitude O degrees North, the areas around this geographical location is referred to as the arctic.

Now , there is an estimated 1/4 or 25% of the world’s oil and natural gas here. Unfortunately, these are yet accessible because of the amount of ice or snow covering. With increase in technological advancements, this might be accessible in the nearest future

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katovenus [111]

Answer:

Explanation:

Molar heat capacity at constant volume Cv  of a gas = n x .5 R where n is degree of freedom of the gas molecules

CO₂ is a linear molecule , so number of degree of freedom =  3 + 2 = 5

3 is translational and 2 is rotational degree of freedom . There is no vibrational degree of freedom given .

So Cv = 5 / 2 R

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4 0
3 years ago
How many atoms are in 4 mol Zn?
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To covert from moles to atoms times the number of moles by Avogadro's Number (6.022×10²³)

4.0 × 6.022×10²³ = 2.4088×10^24
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3 years ago
If the copper cube had a mass of 28.7 grams and a volume of 3.2 mL, what would its density be?
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Answer:

ρ=m÷v

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3 0
3 years ago
Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

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3 years ago
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GenaCL600 [577]
B. It has a negative charge and much less mass than a proton. 
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