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xxMikexx [17]
3 years ago
15

Proteins are

Chemistry
2 answers:
Nesterboy [21]3 years ago
7 0

Answer:

I would say B

Explanation:

If I'm wrong I apologize, have a good day

ioda3 years ago
4 0

\huge \mathfrak \red{hello...}

\blue{The \:  correct \:  answer \:  is \:  (C).}

<h3>Thanku...</h3>
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Mengapa garam NaNO2 dapat membirukan kertas lakmus merah? Jelaskan dengan reaksi kimianya!
Reika [66]
Can't understand this. English Please!  :) :)
8 0
3 years ago
The process of an atom releasing energy when it moves to a lower energy state is called
Inga [223]
The process of an atom releasing energy when it moves to a lower energy state is called emission.
4 0
3 years ago
If 26.2 mL of AgNO3 is needed to precipitate all the Cl− ions in a 0.785-mg sample of KCl (forming AgCl), what is the molarity o
sweet-ann [11.9K]

<u>Answer:</u>

<em>The molarity of the AgNO_3 solution is 4.02 \times 10^4 M </em>

<em></em>

<u>Explanation:</u>

The Balanced chemical equation is

1AgNO_3 (aq) +1KCl (aq) > 1 AgCl (s)+1KNO_3 (aq)

Mole ratio of AgNO_3 : KCl is 1 : 1

So moles AgNO_3  = moles KCl

Moles KCl = \frac {mass}{molarmass}

= \frac {0.785 mg}{(39.1+35.5 g per mol)}

= \frac {0.000785 g}{74.6 g  per mol}

= 0. 0000105 mol KCl

= 0.0000105 mol AgNO_3

So  Molarity

= \frac {moles of solute}{(volume of solution in L)}

= \frac {0.0000105 mol}{26.2 mL}

=\frac {0.0000105 mol}{0.0262 L}

= 0.000402M or mol/L is the Answer

(Or) 4.02 \times 10^4 M is the Answer

6 0
3 years ago
Why doesn't glass exhibit crystalline form
ser-zykov [4K]
It doesn't have a 3 dimensional pattern
7 0
3 years ago
The position of equilibrium would not be appreciably affected by changes in the volume of the container for
8090 [49]

Answer:

The position of equilibrium would not be appreciably affected by changes in the volume of the container for  NiO(s) + CO(g) ⇌ Ni(s) + CO2(g).

Correct Answer : Option A

Explanation:

The equilibrium position tends to change with increase or decrease in pressure or volume, or both of them. This happens because considering change in volume, when the volume of the container increases, the reactant molecule increases i.e. mole of gases and thus the position of equilibrium shifts towards the right side. Similarly in case of decreasing volume, reactant molecule decreases and the equilibrium position shifts left side.

And in case, when the mole of gases on both the sides of the equation i.e. reactant side and product side are equal, it will not have any effect on the equilibrium position on increasing or decreasing volume, or pressure.

4 0
3 years ago
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